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Thomas Calculus 13th [Solutions]

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82 Chapter 2 Limits and Continuity<br />

8. (a) (b)<br />

(c)<br />

lim f ( x) 0 lim f ( x)<br />

x<br />

1 x 1<br />

Yes, lim f ( x ) 0 since the right-hand and left-hand<br />

x<br />

1<br />

limits exist and equal 0<br />

9. (a) domain: 0 x 2<br />

range: 0 y 1 and y 2<br />

(b) lim f ( x)<br />

exists for c belonging to (0, 1) (1, 2)<br />

x c<br />

(c) x 2<br />

(d) x 0<br />

10. (a) domain: x<br />

range: 1 y 1<br />

(b) lim f ( x)<br />

exists for c belonging to<br />

x<br />

c<br />

( , 1) ( 1, 1) (1, )<br />

(c) none<br />

(d) none<br />

11. lim x 2 0.5 2 3/2<br />

x 1 0.5 1 1/2<br />

3<br />

x 0.5<br />

12. lim x 1 1 1<br />

x 2 1 2<br />

0 0<br />

x 1<br />

2( 2) 5<br />

13. lim x 2x<br />

5 2 (2) 1 1<br />

x 1 2 2 1 2<br />

( 2) ( 2) 2<br />

x 2 x x<br />

14. lim 1 x 6 3 x 1 1 6 3 1 1 7 2<br />

x 1 x 7 1 1 1 7 2 1 7<br />

1<br />

x 1<br />

15.<br />

2 2 2<br />

h 4h 5 5 h 4h 5 5 h 4h<br />

5 5<br />

lim<br />

lim<br />

h<br />

h<br />

2<br />

h 0 h 0<br />

h 4h<br />

5 5<br />

h( h 4)<br />

lim<br />

0 4 2<br />

2<br />

h 0 h h 4h<br />

5 5 5 5 5<br />

2<br />

( h 4h<br />

5) 5<br />

lim<br />

2<br />

h 0 h h 4h<br />

5 5<br />

16.<br />

2 2 2<br />

6 5h 11h 6 6 5h 11h 6 6 5h 11h<br />

6<br />

lim<br />

lim<br />

h<br />

h<br />

2<br />

h 0 h 0<br />

6 5h<br />

11h<br />

6<br />

2<br />

6 (5h 11h 6) h(5h<br />

11) (0 11)<br />

lim<br />

lim<br />

11<br />

2 2<br />

h 0 h 6 5h 11h 6 h 0 h 6 5h 11h<br />

6 6 6 2 6<br />

Copyright<br />

2014 Pearson Education, Inc.

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