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Thomas Calculus 13th [Solutions]

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1104 Chapter 15 Multiple Integrals<br />

24. The area of the region R is 4 times the shaded in the following figure.<br />

y<br />

2<br />

1<br />

0 1 2<br />

x<br />

The area integral will be easy to compute in polar coordinates, but in rectangular coordinates the calculation is<br />

awkward.<br />

R<br />

1<br />

4 x<br />

2<br />

4<br />

2 2<br />

x<br />

3 2 3 3<br />

dA 4<br />

2<br />

1 dy dx 1dy dx 4 4 3<br />

2 12 3 2 4<br />

0<br />

1 x<br />

1<br />

0<br />

(As in Exercise 23, use integration by parts to evaluate the integrals<br />

2<br />

4 x dx and<br />

2<br />

1 x dx . )<br />

Geometrically the area is the difference between the area of a circle of radius 2 and the area of a circle of radius<br />

1, or 4 3 .<br />

25.<br />

5 0 y<br />

10,000e 2 5 2 0 5<br />

dy dx 10,000 1 e<br />

dx<br />

10,000 1 e<br />

dx dx<br />

5 2 1 5 1<br />

5 1 0 1<br />

x<br />

x<br />

2 2<br />

2<br />

0<br />

2<br />

5<br />

x<br />

e<br />

x<br />

2 5 2 0<br />

10,000 1 e 2 ln 1 10,000 1 2 ln 1<br />

x<br />

x<br />

2 2<br />

2 5 2 5 2 7<br />

2 2 2<br />

10,000 1 e 2 ln 1 10,000 1 e 2 ln 1 40,000 1 e ln 43,329<br />

26.<br />

2 2<br />

1 2 y y<br />

1 2 y y 1 2 1 3<br />

2 100( 1) 100( 1)<br />

2<br />

100( 1) 2 2 200<br />

0 y<br />

0 y<br />

0 0<br />

y dx dy y x dy y y y dy y y dy<br />

2<br />

y<br />

4<br />

y<br />

1 1<br />

2 4<br />

0<br />

4<br />

200 (200) 50<br />

27. Let ( x , y ) be the location of the weather station in county i for i 1, , 254. The average temperature in<br />

i<br />

i<br />

254<br />

T ( x , y ) A<br />

i i i<br />

i 1<br />

Texas at time t 0 is approximately<br />

, where T( x , )<br />

A<br />

i y i is the temperature at time t 0 at the weather<br />

station in county i,<br />

A is the area of country i, and A is the area of Texas.<br />

i<br />

28. Let y f ( x ) be a nonnegative, continuous function on [ a, b ], then<br />

b<br />

f ( x ) dx a<br />

R<br />

b f ( x) b f ( x)<br />

a 0<br />

a 0<br />

A dA dy dx y dx<br />

29. Since f is continuous on R , if m f ( x, y) M , property 3(b) of double integrals gives us<br />

m dA f ( x, y)<br />

dA M dA and hence mA( R) f ( x, y) dA MA( R).<br />

R R R<br />

R<br />

Copyright<br />

2014 Pearson Education, Inc.

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