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Thomas Calculus 13th [Solutions]

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Section 16.2 Vector Fields and Line Integrals: Work, Circulation, and Flux 1167<br />

dr<br />

dr<br />

1 dt<br />

1 dt<br />

1 1 2 2 2 2 2<br />

33. F ( a sin t ) i ( a cos t ) j, ( a sin t ) i ( a cos t ) j F a sin t a cos t a<br />

2 2<br />

1<br />

0<br />

1 1<br />

Circ a dt a ; M a sin t, N a cos t, dx a sin t dt, dy a cos t dt<br />

0<br />

2 2<br />

Flux1 1 1<br />

sin cos sin cos 0;<br />

C M dy N dx a t t a t t dt 2 2<br />

F2 tj, i F2<br />

0<br />

dt<br />

dt<br />

Circ 0; M 0, N t , dx dt , dy 0 Flux M dy N dx t dt 0; therefore,<br />

2 2 2 2<br />

C<br />

2 2<br />

2<br />

1 2 a<br />

1 2<br />

Circ Circ Circ and Flux Flux Flux 0<br />

2 2 2 2 dr<br />

dr<br />

1 1<br />

3 3 3 3<br />

dt<br />

dt<br />

1 1<br />

34. F a sin t i a cos t j, ( a sin t ) i ( a cos t ) j F a sin t a cos t<br />

35. (a)<br />

(b)<br />

3 3 3 3 4 3 2 2 2 2<br />

1<br />

0<br />

3 1 1<br />

Circ a sin t a cos t dt a ; M a sin t , N a cos t , dy a cos t dt , dx a sin t dt<br />

3 2 3 2 2 3<br />

1 1 1<br />

0<br />

3<br />

Flux cos sin sin cos ;<br />

C M dy N dx a t t a t t dt a 2 2<br />

F2 t j, i F2<br />

0<br />

dt<br />

dt<br />

2 a 2 2 3<br />

2 2 2 2<br />

C<br />

2 2<br />

a<br />

3<br />

4 3<br />

1 2 a<br />

3<br />

1 2<br />

Circ 0; M 0, N t , dy 0, dx dt Flux M dy N dx t dt a ; therefore,<br />

Circ Circ Circ and Flux Flux Flux 0<br />

2 2<br />

r (cos t) i (sin t) j, 0 t , and F ( x y) i x y j ( sin t) i (cos t) j and<br />

d r<br />

dt<br />

2 2 dr<br />

2<br />

dt<br />

F (cos t sin t ) i cos t sin t j F sin t cos t sin t cos t F T ds<br />

2 1 2 sin 2t<br />

sin t cos t sin t cos t dt sin t<br />

t<br />

sin t<br />

0 2 2 4<br />

0<br />

2<br />

a<br />

a<br />

dr<br />

C<br />

2<br />

dr<br />

2 2 d r<br />

2<br />

dt<br />

r (1 2 t) i, 0 t 1, and F ( x y) i x y j 2i and F (1 2 t) i (1 2 t)<br />

j<br />

F<br />

dr<br />

dt<br />

4 t 2 F T ds (4 t 2) dt 2 t 2 t 0<br />

C<br />

1 2<br />

1<br />

0 0<br />

2 2 dr<br />

2<br />

dt<br />

1<br />

(c) r1 (1 t) i tj, 0 t 1, and F ( x y) i x y j i j and F (1 2 t) i 1 2t 2t<br />

j<br />

dr<br />

2 2 dr<br />

1 2 2<br />

1 1<br />

F<br />

dt<br />

t t t t 1 F<br />

C dt<br />

3 2<br />

1 0<br />

t dt r t i t j<br />

(2 1) 1 2 2 2 Flow 2 ; ( 1) ,<br />

2 2 d r<br />

2 2<br />

dt<br />

2<br />

0 t 1, and ( x y) x y and t t 2t<br />

1<br />

F i j i j F i j<br />

2 dr<br />

2 2 dr<br />

1 2<br />

i t t j F t t t t F t t dt<br />

t<br />

2 2<br />

2 2 1 1 2 2 1 2 2 Flow2<br />

2 2<br />

dt<br />

C dt<br />

2 0<br />

2 3<br />

1<br />

2<br />

t<br />

1 2 1<br />

3 3 1 2<br />

0<br />

3 3<br />

Flow Flow Flow 1<br />

2 2<br />

1<br />

36. From (1,0) to (0,1): r1 (1 t) i tj, 0 t 1, and F ( x y) i x y j i j,<br />

2 2 1 2 2 3<br />

1<br />

2 1<br />

1 1 1 1 1<br />

0 3 0 3<br />

2 2 dr<br />

r2 ti (1 t) j, 0 t 1, and F ( x y) i x y j i j,<br />

dt<br />

F i 1 2t 2 t j, and n | v | i j F n | v | 2t 2t Flux 2t 2 t dt t t ;<br />

From (0, 1) to ( 1, 0):<br />

2<br />

2 2 2<br />

2 2 2 2<br />

F (1 2 t) i 1 2t 2 t j, and n | v | i j F n | v | (2t 1) 1 2t 2t 2 4t 2t<br />

1 2 2 3<br />

1<br />

2 2<br />

2 t t dt t t t<br />

0 3 0 3<br />

Flux 2 4 2 2 2 ;<br />

dr<br />

dt<br />

dr<br />

dr<br />

Copyright<br />

2014 Pearson Education, Inc.

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