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Thomas Calculus 13th [Solutions]

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956 Chapter 13 Vector-Valued Functions and Motion in Space<br />

14. By Exercise 14 in Section 13.4, T cost<br />

i sin t j and N sin t i cost<br />

j so that<br />

i j k<br />

B T N cos t sin t 0 k . Also, v<br />

2<br />

3cos t sin t i<br />

2<br />

3sin t cost<br />

j<br />

sin t cost<br />

0<br />

a d 2 2 2 2<br />

3cos sin d d a<br />

t t i 3sin t cost j d d 3cos t sin t i d d 3sin t cost<br />

dt dt dt dt dt dt dt<br />

j<br />

2<br />

3cos t sin t<br />

2<br />

3sin t cost<br />

0<br />

d 2 2<br />

3cos t sin t d 3sin t cost<br />

dt<br />

dt<br />

0 0 0<br />

d d 2 2<br />

3cos t sin t d d 3sin t cost<br />

dt dt dt dt<br />

0<br />

15. By Exercise 15 in Section 13.4, T v sech t tanh t<br />

v a<br />

i a<br />

j and N tanh t sech t<br />

a<br />

i a<br />

j so that<br />

i j k<br />

B T N sech t tanh t 0 k . Also, sinh t 1 cosh t d a<br />

v i j a j 1 sinh t j so<br />

a<br />

a<br />

a a a dt 2<br />

a a<br />

tanh t sech t 0<br />

a a<br />

1 sinh t 0<br />

a<br />

that 0 1 cosh t 0 0 0<br />

a a<br />

0 1 sinh t 0<br />

2<br />

a a<br />

16. By Exercise 16 in Section 13.4, T 1 tanh t i 1 j 1 sech t<br />

2 2 2<br />

k and N sech t i tanh t k so that<br />

i j k<br />

B T N 1 tanh t 1 1 sech t 1 tanh t i 1 j 1 sech t<br />

2 2 2 2 2 2<br />

k . Also, v sinh t i cosh t j k<br />

sech t 0 tanh t<br />

i j k<br />

a cosh t i sinh t j<br />

d a<br />

dt<br />

sinh t i cosh t j and v a sinh t cosh t 1<br />

cosh t sinh t 0<br />

sinh t i cosh t j<br />

2<br />

cosh t<br />

2<br />

sinh t k sinh t i cosh t j k v<br />

2<br />

a<br />

2<br />

sinh t<br />

2<br />

cosh t 1. Thus<br />

sinh t cosh t 1<br />

cosh t sinh t 0<br />

sinh t cosh t 0 1 1 .<br />

2 2 2 2 2<br />

sinh t cosh t 1 sinh t cosh t 1 2cosh t<br />

17. Yes. If the car is moving along a curved path, then<br />

2<br />

0 and aN k | v | 0 a aT T aN<br />

N 0.<br />

18. v constant a d<br />

T v 0 a a<br />

dt<br />

N N is orthogonal to T the acceleration is normal to the path<br />

19. a v a T a 0 d<br />

T v 0 v is constant<br />

dt<br />

Copyright<br />

2014 Pearson Education, Inc.

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