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Thomas Calculus 13th [Solutions]

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1052 Chapter 14 Partial Derivatives<br />

14.9 TAYLORS FORMULA FOR TWO VARIABLES<br />

y<br />

x y y y xx xy y yy<br />

y<br />

1. f ( x, y) xe f e , f xe , f 0, f e , f xe<br />

1 2 2<br />

f ( x, y) f (0, 0) x fx (0, 0) y f y (0, 0) x f (0, 0) 2 (0, 0) (0, 0)<br />

2 xx xy fxy y f yy<br />

1 2 2<br />

0 x 1 y 0 x 0 2xy 1 y 0 x xy quadratic approximation;<br />

2<br />

y<br />

y<br />

fxxx 0, fxxy 0, fxyy e , f yyy xe<br />

1 3 2 2 3<br />

f ( x, y) quadratic x f (0, 0) 3 (0, 0) 3 (0, 0) (0, 0)<br />

6 xxx x yfxxy xy fxyy y f yyy<br />

1 3 2 2 3 1 2<br />

x xy x 0 3x y 0 3xy 1 y 0 x xy xy , cubic approximation<br />

6 2<br />

x x x x x x<br />

2. f ( x, y) e cos y fx e cos y, f y e sin y, fxx e cos y, fxy e sin y, f yy e cos y<br />

1 2 2<br />

f ( x, y) f (0, 0) x fx (0, 0) y f y (0, 0) x f (0, 0) 2 (0, 0) (0, 0)<br />

2 xx xy fxy y f yy<br />

1 2 2 1 2 2<br />

1 x 1 y 0 x 1 2xy 0 y ( 1) 1 x x y , quadratic approximation;<br />

2 2<br />

x x x x<br />

fxxx e cos y, fxxy e sin y, fxyy e cos y, f yyy e sin y<br />

1 3 2 2 3<br />

f ( x, y) quadratic x f (0, 0) 3 (0, 0) 3 (0, 0) (0, 0)<br />

6 xxx x yfxxy xy fxyy y f yyy<br />

1 2 2 1 3 2 2 3<br />

1 x x y x 1 3x y 0 3 xy ( 1) y 0<br />

2 6<br />

1 2 2 1 3 2<br />

1 x x y x 3 xy , cubic approximation<br />

2 6<br />

3. f ( x, y) y sin x fx y cos x, f y sin x, fxx y sin x, fxy cos x, f yy 0<br />

1 2 2<br />

x y 2 xx xy yy<br />

f ( x, y) f (0, 0) x f (0, 0) y f (0, 0) x f (0, 0) 2 xy f (0, 0) y f (0, 0)<br />

1<br />

2<br />

2 2<br />

0 x 0 y 0 x 0 2xy 1 y 0 xy , quadratic approximation;<br />

fxxx y cos x, fxxy sin x, fxyy 0, f yyy 0<br />

1<br />

6<br />

3 2 2 3<br />

xxx xxy xyy yyy<br />

f ( x, y) quadratic x f (0, 0) 3 x yf (0, 0) 3 xy f (0, 0) y f (0, 0)<br />

1<br />

6<br />

3 2 2 3<br />

xy x 0 3x y 0 3xy 0 y 0 xy , cubic approximation<br />

4. f ( x, y) sin x cos y fx cos x cos y, f y sin x sin y, fxx sin x cos y, fxy<br />

cos x sin y,<br />

f sin x cos y<br />

yy<br />

1<br />

2<br />

1 2 2<br />

x y 2 xx xy yy<br />

f ( x, y) f (0, 0) x f (0, 0) y f (0, 0) x f (0, 0) 2 xy f (0, 0) y f (0, 0)<br />

2 2<br />

0 x 1 y 0 x 0 2xy 0 y 0 x , quadratic approximation;<br />

fxxx cos x cos y, fxxy sin x sin y, fxyy cos x cos y, f yyy sin x sin y<br />

1<br />

6<br />

3 2 2 3<br />

xxx xxy xyy yyy<br />

f ( x, y) quadratic x f (0, 0) 3 x yf (0, 0) 3 xy f (0, 0) y f (0, 0)<br />

1 3 2 2 3 1 3 2<br />

6 6<br />

x x ( 1) 3x y 0 3 xy ( 1) y 0 x x 3 xy , cubic approximation<br />

Copyright<br />

2014 Pearson Education, Inc.

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