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Thomas Calculus 13th [Solutions]

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1106 Chapter 15 Multiple Integrals<br />

14.<br />

2 x /4 2 sec 2 8<br />

/4<br />

y dy dx r<br />

2<br />

sin dr d tan sec<br />

4<br />

0 0 0 0 3 d<br />

0<br />

3<br />

15.<br />

3 x /4 3 sec /4<br />

3 2 1 2<br />

3 1<br />

/4<br />

dy dx r dr d<br />

1 1 /6 csc /6 2 2 d<br />

2 2 /6<br />

sec csc tan cot 2 3<br />

2 y<br />

/2 2 csc /4 2 1<br />

/2<br />

dy dx r dr d 2csc 2 d 2 cot 2<br />

2 4 y<br />

/4 2 /6 2 /4 2<br />

16. 2<br />

0 0<br />

2<br />

3 /2 1 3 /2 1 3 /2<br />

dy dx 2r<br />

dr d 1 dr d d<br />

1 1 x 2 2<br />

1 x y<br />

0 1 r<br />

0 1 r<br />

17. 2<br />

2 1 2 (1 ln 2) (1 ln 2)<br />

18.<br />

2<br />

1 1 x<br />

1<br />

2<br />

/2 1 /2 /2<br />

2 dy dx 2 1<br />

1 1 4 r dr d<br />

2 2 2<br />

2 2 0 0 4 d<br />

2<br />

1 1<br />

0 2 d<br />

x<br />

x y r<br />

1 r 0 0<br />

19.<br />

2 2 2 2<br />

ln 2 (ln 2) y x y /2 ln 2 r<br />

/2<br />

e dx dy re dr d d<br />

0 0 0 0 0<br />

(2ln 2 1) (2ln 2 1)<br />

2<br />

20.<br />

2<br />

1 1 y 2 2 /2 1 2<br />

/2<br />

x y dx dy r r dr d d<br />

1 2<br />

1 y<br />

0 0 0<br />

ln 1 4 ln 1 2 (ln 4 1) (ln 4 1)<br />

21.<br />

2<br />

1 2 x<br />

/2 2 /2<br />

2<br />

0 ( x 2 y ) dy dx<br />

/4 0 ( r cos 2 r sin ) r dr d r<br />

/4 3 cos r<br />

3<br />

sin d<br />

x<br />

0<br />

/2 /2 2 2 4 2 2 2 4 2<br />

2 1 2<br />

cos sin d sin cos<br />

/4 3 3 3 3 3<br />

/4<br />

3 3 2<br />

22.<br />

2<br />

2 2 x x<br />

2cos<br />

1<br />

/4 2cos /4 /4 2 2<br />

dy dx 1 r dr d 1 d 1<br />

cos<br />

1<br />

sec d<br />

1 0<br />

2 4 2<br />

2 2<br />

0 sec r<br />

0 2r<br />

sec 0 2 8<br />

x y<br />

/4<br />

1 1<br />

sin 2<br />

1<br />

tan<br />

4 8 8 0 16<br />

23.<br />

1 1<br />

0 0<br />

2<br />

2<br />

x 1 1 y<br />

x y dy dx<br />

0 0<br />

x y dy dx<br />

Copyright<br />

2014 Pearson Education, Inc.

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