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Thomas Calculus 13th [Solutions]

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444 Chapter 6 Applications of Definite Integrals<br />

8. a 0, b 1;<br />

b shell shell 1<br />

V 2 radius height dx 2 x 2x x dx<br />

a<br />

0<br />

2<br />

1<br />

3<br />

1 2 3<br />

0 2 x dx<br />

2<br />

0 3 x dx x<br />

0<br />

2 1<br />

9. a 0, b 1;<br />

b shell shell 1<br />

2<br />

V 2 radius height dx 2 x (2 x)<br />

x dx<br />

a<br />

0<br />

2 1 2 3 2<br />

0 2 x x x dx 2 x x x<br />

3 4<br />

0<br />

2 1 1 1 2 12 4 3 10 5<br />

3 4 12 12 6<br />

10. a 0, b 1;<br />

3 4 1<br />

b shell shell 1<br />

2 2<br />

V 2 radius height dx 2 x 2 x x dx<br />

a<br />

0<br />

1 2 1 3<br />

2 x 2 2x dx 4 x x dx<br />

0 0<br />

2 4<br />

4 x x<br />

1 4 1 1<br />

2 4<br />

0<br />

2 4<br />

11. a 0, b 1;<br />

V<br />

b shell shell 1<br />

2 radius height dx 2<br />

a<br />

0<br />

x x (2x 1) dx<br />

2<br />

1 3/2 2 5/2 3 2<br />

1<br />

x 2x x dx 2 2 x 2 x 1 x<br />

0 5 3 2 0<br />

2 2 2 1 2 12 20 15 7<br />

5 3 2 30 15<br />

12. a 1, b 4;<br />

b shell shell 4<br />

3 1/2<br />

V 2 radius height dx 2 x x dx<br />

a<br />

1 2<br />

4 1/2 3/2<br />

4<br />

3 x dx 3 2 x 2 4 3/2<br />

1<br />

1 3 1<br />

2 (8 1) 14<br />

13. (a)<br />

x sin x , 0 x sin x, 0 x<br />

x f ( x) x<br />

x f ( x) ;<br />

x, x 0<br />

0, x 0<br />

since sin 0<br />

0 we have<br />

sin x, 0 x<br />

x f ( x) x f ( x) sin x, 0 x<br />

sin x, x 0<br />

Copyright<br />

2014 Pearson Education, Inc.

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