The 'New Berlin' base: Nazis in the Antarctic - Project Camelot

And can one also derive the Photon-Rotation Energy ħ = h • 1 /2π (Ergänzung von mir):
In order to derive the Rotation Energy ħ = h • 1 /2π watch at first this picture:
the field of the photon The 3-dim room in the photon
K or C
V*
355
Moving around and around also with
the velocity C or K.
the ether of an other bigger photon?
So as you see the 3-dim room in the Photon also all the time moves around and around. One part ( 1 / 2M) moves around and
around with the velocity V 1 = 2C, the other part ( 1 / 2M) with the velocity V 2 = 0 (Remains on the orange line). All this you
also can see at this picture:
With: PRot = 2 • C • 1 /2M = MC = P
and: P0 = 0 • 1 /2M = 0 C or K
V*
R
PRot • m
1 /2M
P0 = 0
?
1 /2M
λ = 2 π R (with R the maxime radius of the Photon/Universe)
Or as well one maybe also can say that the field of the mass M (grey plane) and therefore also the mass M turns around and
around with the velocity C in a circle with the radius R. Therefore the mass M should have the rotating-impulse PRot = MC
when it comes in a not rotating field.
We know now that also the room in the Photon has an impulse P because of its movement through the room with the velocity
C. I assume now that this impulse P = PRot the impulse with which the same “internal” mass M in the Photon goes around
and around in a circle! Because both have the same mass M and the same velocity C!
Moreover I want to say: Over the time the impulse PRot also should not produce an resulting impulse P’ in one direction. I
think, the reason for that is that he all the time moves around and around in a circle.
Moreover I want to say: We have not considered that the 3-dim field in the room has an different thickness in each moment.
But that doesn’t matter. Because we also can use an middle-worth for the impulse PRot or P over the time. Our results will be
then the same like without middle-worth.
Next I want to calculate the Rotation-impulse L = PRot • R of our Photon. We already know that PRot = P = h /λ .
Moreover we know that λ = 2 π R (compare upstairs). These two equations we use now to calculate L:
L = PRot • R
L = P • R (P = PRot)
L = h /λ • R (first equation)
L = h /2 π R • R (second equation)
L = h /2 π
So as you see each Photon-Quant should not only have an constant Energy h but also an constant Rotating-impulse L = ħ =
h • 1 /2π . Maybe all this also can explain why there also exist Rotation-impulses L = h • 1 /4π (for example in the electron).
This one can explain for example when the direction of the Rotation in the Photon changes after the time-period λ /2 (First