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ITT - Index of

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APPLICATION NOTES<br />

FOUR-LAYER DIODE<br />

A<br />

Figure 21<br />

REGULAR<br />

POWER<br />

SUPPLY<br />

EMERGENCY<br />

POWER<br />

SUPPLY<br />

Figure 19<br />

Emergency Power Transfer<br />

In the normal state, the 4-loyer diode in<br />

Figure 19 is OFF and the regular power supply<br />

is the source <strong>of</strong> power for the load RL. If the<br />

supply voltage should fall <strong>of</strong>f for any reason,<br />

the voltage at point A will drop. If this change<br />

in voltage is sufficient to cause the potential<br />

from 8 to A to exceed the diad .. V" it will turn<br />

ON and the emergency power supply will<br />

provide power to the load until the condition<br />

is corrected.<br />

In Figure 21, succeeding half cycles can<br />

have different firing angles since there are two<br />

control diodes, One for each leg <strong>of</strong> the rectifier<br />

circuit.<br />

A.C.<br />

C'<br />

Figure 20<br />

1J<br />

Rectifier Control Circuits<br />

Figure 20 illustrates a method for controlling<br />

the power output <strong>of</strong> a rectifier by varying the<br />

point at which a 4-layer diode is triggered.<br />

Pulses may be applied at any phase angle<br />

from the start <strong>of</strong> the input waveform (100%<br />

power! to 180° (zero power!.<br />

AC Control Circuits<br />

The circuit in Figure 22 is useful for the control<br />

<strong>of</strong> AC power in such applications as light<br />

dimmers and motor controls. The trigger portion<br />

is composed <strong>of</strong> two back-to-back relaxation<br />

oscillators with an adjustable resistor COntrolling<br />

the time at which they fore the control<br />

diodes and thus the amount <strong>of</strong> current through<br />

the load.<br />

The load resistor <strong>of</strong> the oscillator and C set<br />

up the time constant to fore the trigger diodes<br />

at approximately 90° in each half cycle. When<br />

a positive input cycle occurs the diode A will<br />

break down at approximately 90°. The charged<br />

capacitor C will discharg e through diad e A<br />

with the result that a negative pulse will appear<br />

at point CI.<br />

This pulse will turn ON control diad e AI which<br />

will allow current to flow until the half cycle is<br />

completed. 80th diodes will then turn OFF<br />

since the current through them will drop below<br />

their holding current. This cycle is repeated<br />

during the negative portion <strong>of</strong> the input waveform.<br />

15-12

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