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N. 3 - 21 aprile 2001 - Giano Bifronte

N. 3 - 21 aprile 2001 - Giano Bifronte

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case of the AC effect which involves the interaction between a moving<br />

neutral magnetic dipole and the external electric field , the approach of<br />

Boyer, has been criticized by Aharonov, Pearle and Vaidman [7] (APV)<br />

for not taking into account the hidden momentum of the magnetic<br />

dipole.<br />

As already mentioned, the intriguing aspect of these nonlocal effects<br />

is that there is an observable displacement of the interference pattern<br />

even though there are no forces acting locally on the beam of particles.<br />

Here, the expression of the forces (for example, the Lorentz force) is the<br />

one given by the relativistic interpretation of electrodynamics. If the<br />

relativistic expression of the force is correct, then these effects are<br />

surely nonlocal because the force is zero in the experimental conditions<br />

that lead to these effects.<br />

However, if the nature of these effects were not nonlocal and were<br />

instead due to a local interaction, then it would imply that the<br />

relativistic expression for the force is incorrect so that the actual force<br />

on the beam of particles could turn out to be non-null.<br />

In the next sections we consider in detail how, within a nonrelativistic<br />

interpretation of classical electrodynamics, the em force on elementary<br />

particles may differ from the relativistic expression.<br />

3 - A modified expression of the Lorentz force<br />

We consider here two cases: modification of the Lorentz force due to<br />

the hypothetical existence of longitudinal forces in agreement with the<br />

integral form of the Faraday Law; test of the validity of the Lorentz<br />

force for the differential form of Faraday's Law.<br />

3.1 - longitudinal forces<br />

Making use of the connective derivative d/dt = ∂t + v.∇ , from<br />

Faraday's Law for a moving loop, the electromotive force (emf) ΔV<br />

may be expressed by means of the effective field Eeff as<br />

ΔV = ∫ Eeff.dl = -(1/c) d<br />

dt ∫ B.ds = -(1/c) ∫ (∂tA+v×B).dl . (2)<br />

Using vector identities we may write<br />

-(1/c) ∫ (v.∇)A.dl = -(1/c) ∫ [∇(v.A)+v×B].dl = (1/c) ∫ (v×B).dl , (3)<br />

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