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N. 3 - 21 aprile 2001 - Giano Bifronte

N. 3 - 21 aprile 2001 - Giano Bifronte

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184<br />

In the second case b), the standard Lorentz force is zero because,<br />

according to SR, there are no fields outside the moving solenoid which<br />

becomes also electrically polarized. However, the nonstandard<br />

expression, which in a nonrelativistic formulation does not foresee<br />

electric polarization, predicts an impulse<br />

∫ fdt = -QAm ,<br />

in the direction of v , of the same order of magnitude of that due to the<br />

force QEm . Here, a non-null result favors the nonrelativistic<br />

interpretation.<br />

4 - Test of the fields produced by an open current<br />

As mentioned in the Introduction, all the existing tests of the fields<br />

produced by moving charges refer to charges moving in closed circuits<br />

(closed currents). The magnetic field produced by an isolated moving<br />

charge (open current) has never been tested.<br />

If a charge is placed in the laboratory reference frame it produces a<br />

static electric field in that frame. According to relativity a frame moving<br />

with respect to the laboratory will experience also a magnetic field. In<br />

fact, for relativity the moving charge forms a current and the charge and<br />

current density transform as a four-vector. Thus, by Maxwell's<br />

equations the current generates a magnetic field even though there is<br />

only an electric field in the rest frame of the charge. In a nonrelativistic<br />

interpretation of electrodynamics, a current may be defined as due to<br />

charges moving in a closed circuit. Isolated charges may not form a true<br />

current even if they move with respect to some observer (open current).<br />

To many physicists the idea that open currents are not true currents<br />

generating a magnetic field may seem to be untenable. However, we<br />

recall that the physical behavior of charges moving in a closed circuit is<br />

quite different than that of open currents. For example, the correct (for<br />

relativity) expression of the force on a magnetic dipole has to take into<br />

account the fact that the moving charges forming the dipole current are<br />

linked to the closed loop forming the dipole m . There are internal<br />

stresses contributing to the correct force on m that do not exist for open<br />

currents. Thus it is not unreasonable to think that the forces acting on,<br />

or the fields generated by, open currents may differ from those due to<br />

closed currents. Furthermore, the motion of charges in a closed circuit is<br />

a kind of absolute motion (with respect to the frame at rest with the

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