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MATEMAATILINE ANALÜÜS II - Tallinna Tehnikaülikool

MATEMAATILINE ANALÜÜS II - Tallinna Tehnikaülikool

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162 PEATÜKK 3. INTEGRAALARVUTUS<br />

y ✻ <br />

. y = x + 2<br />

4<br />

.<br />

..<br />

3<br />

.<br />

y = x 2 .<br />

.. D<br />

.<br />

.<br />

. .<br />

.. ..<br />

. .. ..<br />

.. .. .. .. ✲<br />

x<br />

.. .. .....<br />

−1 1 2 3<br />

Et<br />

{ y = x<br />

2<br />

y = x + 2<br />

⇒ P 1 (−1; 1) , P 1 (2; 4) ,<br />

siis valemi (3.4.1) abil saame<br />

∫∫ ∫ 2 x+2 ∫ ∫ 2<br />

(<br />

S D = dxdy = dx dy = 2 + x − x<br />

2 ) dx =<br />

D<br />

−1 x 2 −1<br />

( 1<br />

=<br />

2 x2 + 2x − 1 )∣ ∣∣∣<br />

2<br />

3 x3 = 9 2 . ♦<br />

−1<br />

Näide 2. Leiame joontega<br />

√ x<br />

a + √ y<br />

b<br />

= 1 (a, b > 0) , x = 0, y = 0<br />

piiratud piirkonna D pindala.<br />

Skitseerime piirkonna D<br />

y ✻<br />

b..<br />

.<br />

. ...<br />

. ..<br />

.<br />

..<br />

<br />

. ..<br />

D <br />

<br />

.<br />

.<br />

<br />

..<br />

.<br />

.<br />

<br />

.. .. .. .. ..<br />

a<br />

✲x

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