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MATEMAATILINE ANALÜÜS II - Tallinna Tehnikaülikool

MATEMAATILINE ANALÜÜS II - Tallinna Tehnikaülikool

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202 PEATÜKK 3. INTEGRAALARVUTUS<br />

ses suunas. Kasutades Lause 3.10.2 teist osa, saame<br />

∮<br />

Xdx = ∫<br />

Xdx + ∫<br />

Xdx + ∫<br />

Xdx + ∫<br />

Xdx =<br />

Kuna<br />

siis<br />

Γ<br />

⎡<br />

= ⎣<br />

⎡<br />

⎣<br />

[(3.10.6)]<br />

=<br />

= −<br />

AB<br />

BC<br />

CE<br />

AB :<br />

x = x, y = ϕ (x) , dx = dx<br />

−−−−−−→<br />

a ≤ x ≤ b<br />

CE :<br />

x = x, y = ψ (x) , dx = dx<br />

←−−−−−−<br />

a ≤ x ≤ b<br />

=<br />

∫ b<br />

a<br />

∫ b<br />

a<br />

∫ b<br />

a<br />

EA<br />

BC :<br />

x = b, y = y, dx = 0<br />

−−−−−−−−−−−−→<br />

ϕ (b) ≤ y ≤ ψ (b)<br />

EA :<br />

x = a, y = y, dx = 0<br />

←−−−−−−−−−−−−<br />

ϕ (a) ≤ y ≤ ψ (a)<br />

a∫<br />

X (x, ϕ (x)) dx + 0 + X (x, ψ (x)) dx + 0 =<br />

(X (x, ψ (x)) − X (x, ϕ (x))) dx.<br />

∫∫<br />

X y dx dy =<br />

D<br />

∫ b<br />

a<br />

dx<br />

b<br />

ψ(x)<br />

∫<br />

ϕ(x)<br />

X y (x, y) dy =<br />

X (x, y)| ψ(x) b<br />

ϕ(x) dx = ∫<br />

(X (x, ψ (x)) − X (x, ϕ (x))) dx,<br />

∮<br />

Γ<br />

a<br />

∫∫<br />

Xdx = −<br />

D<br />

X y dx dy.<br />

2 ◦ Olgu piirkond D jaotatav y-teljega paralleelsete sirgl~oikudega m x-telje suhtes<br />

normaalseks piirkonnaks D k vastavalt rajajoontega Γ k .<br />

⎤<br />

⎤<br />

⎦<br />

⎦ =<br />

❅■ ✁☛<br />

❅❅<br />

✓✴ ❅❅■<br />

✻❄ ❅✁ ✁✁✁✁✁<br />

✻ ❄<br />

D 3 D<br />

✻<br />

4<br />

✓✴<br />

D5 D m<br />

✤✜ ✜✜✜✜✜✜ ✻❄ ✤✲<br />

✜<br />

❄ D D 2 ❅❘<br />

✻❄<br />

1 ✻❄<br />

✣✘✿<br />

✢ ✣❍❥<br />

✲ ✢

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