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Capitolul 1 Ecuatii diferentiale de ordinul ˆıntâi rezolvabile prin ...

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Problema Cauchy-Dirichlet pentru ecuat¸ii hiperbolice 261<br />

cu |t(X) − t0| ≤ |t − t0| ¸si |t ∗ i (X) − t0| ≤ |t − t0|.<br />

Funct¸iile ∂u<br />

∂t ¸si ∂2u sunt continue ¸si <strong>prin</strong> urmare mǎrginite pe compacte<br />

∂t∂xi<br />

<strong>de</strong> forma [t0 − η, t0 + η] × Ω. Rezultǎ <strong>de</strong> aici cǎ, existǎ o constantǎ pozitivǎ<br />

K2 > 0 astfel ca<br />

U(t) − U(t0) 2<br />

H 1 0<br />

≤ K 2 · |t − t0| 2 ,<br />

<strong>de</strong> un<strong>de</strong> se obt¸ine continuitatea funct¸iei U : [0, +∞) → H 1 0.<br />

iii) Egalitǎt¸ile: U(0) = u0 ¸si U ′ (0) = u1 sunt imediate.<br />

Consi<strong>de</strong>rǎm în continuare spat¸iul <strong>de</strong> funct¸ii S <strong>de</strong>finit <strong>prin</strong>:<br />

S = C([0, +∞); H 1 0 ) ∩ C1 ([0, +∞); L 2 ).<br />

Teorema prece<strong>de</strong>ntǎ aratǎ cǎ, dacǎ u = u(t, X) este o solut¸ie clasicǎ a problemei<br />

(7.36-7.39), atunci funct¸ia U <strong>de</strong>finitǎ <strong>prin</strong> U(t)(X) = u(t, X) apart¸ine<br />

spat¸iului <strong>de</strong> funct¸ii S ¸si verificǎ U(0) = u0, U ′ (0) = u1.<br />

Fie T > 0 ¸si subspat¸iul <strong>de</strong> funct¸ii ST <strong>de</strong>finit <strong>prin</strong>:<br />

ST = {V ∈ S|V (T) = 0}<br />

Teorema 7.4.2 Dacǎ funct¸ia u = u(t, X) este o solut¸ie clasicǎ a problemei<br />

(7.36-7.39), atunci funct¸ia U <strong>de</strong>finitǎ <strong>prin</strong> U(t)(X) = u(t, X) apart¸ine<br />

spat¸iului <strong>de</strong> funct¸ii S, verificǎ U(0) = u0, U ′ (0) = u1 ¸si pentru orice T > 0<br />

¸si orice funct¸ie V ∈ ST are loc egalitatea:<br />

<br />

−<br />

T<br />

0<br />

0<br />

T<br />

< U ′ (t), V ′ (t) > L 2 (Ω) dt− < u1, V (0) > L 2 (Ω) +<br />

< U(t), V (t) >A dt =<br />

T<br />

0<br />

< F(t), V (t) >L 2 (Ω) dt.<br />

(7.40)<br />

Demonstrat¸ie: Apartenent¸a funct¸iei U la spat¸iul S a fost <strong>de</strong>monstratǎ. S-a<br />

arǎtat <strong>de</strong> asemenea cǎ U(0) = u0 ¸si U ′ (0) = u1. Rǎmâne doar sǎ arǎtǎm cǎ

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