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Capitolul 1 Ecuatii diferentiale de ordinul ˆıntâi rezolvabile prin ...

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58 CAPITOLUL 2<br />

în care C1(t), C2(t), C3(t) sunt funct¸ii <strong>de</strong> clasǎ C 1 care trebuiesc <strong>de</strong>terminate.<br />

Calculǎm <strong>de</strong>rivata întâi a funct¸iei x(t) ¸si obt¸inem:<br />

˙x = ˙ C1 + ˙ C2 · e −2t · cos t + ˙ C3 · e −2t · sin t − 2C2 · e −2t · cos t−<br />

− 2C3 · e −2t · sin t − C2 · e −2t · sin t + C3 · e −2t · cost<br />

Impunem ca ˙ C1, ˙ C2, ˙ C3 sǎ verifice:<br />

¸si obt¸inem:<br />

˙C1 + ˙ C2 · e −2t · cost + ˙ C3 · e −2t · sin t = 0<br />

˙x = −C2 · e −2t · (2 cost + sin t) + C3 · e −2t · (cost − 2 sin t)<br />

Calculǎm <strong>de</strong>rivata a doua a funct¸iei x(t) ¸si obt¸inem:<br />

¨x = − ˙ C2 · e −2t · (2 cost + sin t) + ˙ C3 · e −2t · (cost − 2 sin t)+<br />

+2C2 · e −2t · (2 cost + sin t) − 2C3 · e −2t · (cos t − 2 sint)−<br />

−C2 · e −2t · (−2 sin t + cost) + C3 · e −2t · (− sin t − 2 cost) =<br />

= − ˙ C2 · e −2t · (2 cost + sin t) + ˙ C3 · e −2t · (cost − 2 sin t)+<br />

+C2 · e −2t · (3 cost + 4 sin t) + C3 · e −2t · (3 sint − 4 cost).<br />

Impunem ca ˙ C2, ˙ C3 sǎ verifice:<br />

− ˙ C2 · e −2t · (2 cost + sin t) + ˙ C3 · e −2t · (cost − 2 sin t) = 0<br />

¸si obt¸inem<br />

¨x = C2 · e −2t · (3 cost + 4 sin t) + C3 · e −2t · (3 sin t − 4 cost)<br />

De aici calculǎm <strong>de</strong>rivata a treia a funct¸iei x(t) ¸si obt¸inem:<br />

...<br />

x = ˙ C2 · e −2t · (3 cost + 4 sint) + ˙ C3 · e −2t · (3 sin t − 4 cost)−<br />

−2C2 · e −2t · (3 cost + 4 sin t) − 2C3 · e −2t · (3 sint − 4 cost)+<br />

+C2 · e −2t · (−3 sin t + 4 cost) + C3 · e −2t · (3 cost + 4 sin t) =<br />

= ˙ C2 · e −2t · (3 cost + 4 sint) + ˙ C3 · e −2t · (3 sin t − 4 cost)+<br />

+C2 · e −2t · (−2 cost − 11 sint) + C3 · e −2t · (−2 sin t + 11 cost).

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