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Capitolul 1 Ecuatii diferentiale de ordinul ˆıntâi rezolvabile prin ...

Capitolul 1 Ecuatii diferentiale de ordinul ˆıntâi rezolvabile prin ...

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Ecuat¸ii diferent¸iale liniare <strong>de</strong> <strong>ordinul</strong> n cu coeficient¸i constant¸i 59<br />

sau<br />

Înlocuind toate acestea în ecuat¸ia datǎ rezultǎ:<br />

˙C2 · e −2t · (3 cost + 4 sint) + ˙ C3 · e −2t · (3 sin t − 4 cost) +<br />

+C2 · e −2t · (−2 cost − 11 sint) +C3 · e −2t · (−2 sin t + 11 cost) +<br />

+C2 · e −2t · (12 cost + 16 sin t) +C3 · e −2t · (12 sin t − 16 cost) −<br />

−C2 · e −2t · (10 cost + 5 sin t) +C3 · e −2t · (5 cost − 10 sint) = 4e t<br />

˙C2 · e −2t · (3 cost + 4 sin t) + ˙ C3 · e −2t · (3 sin t − 4 cost) = 4e t<br />

Aceastǎ egalitate împreunǎ cu sistemul <strong>de</strong> condit¸ii impus pe parcurs<br />

funct¸iilor ˙ C1, ˙ C2, ˙ C3 conduce la urmǎtorul sistem liniar <strong>de</strong> ecuat¸ii algebrice<br />

în necunoscutele ˙ C1, ˙ C2, ˙ C3:<br />

⎧<br />

⎪⎨<br />

⎪⎩<br />

˙C1 + ˙ C2 · e −2t · cos t + ˙ C3 · e −2t · sin t = 0<br />

− ˙ C2 · e −2t · (2 cost + sin t) + ˙ C3 · e −2t · (cos t − 2 sint) = 0<br />

˙C2 · e −2t · (3 cost + 4 sin t) + ˙ C3 · e −2t · (−4 cost + 3 sin t) = 4e t<br />

Din ultimele douǎ ecuat¸ii rezulǎ sistemul algebric:<br />

⎧<br />

⎨<br />

⎩<br />

˙C2 · (−2 cost − sin t) + ˙ C3 · (cost − 2 sint) = 0<br />

˙C2 · (3 cost + 4 sin t) + ˙ C3 · (−4 cost + 3 sin t) = 4e −t<br />

Determinantul sistemului este:<br />

∆ = (−2 cost − sin t)(−4 cost + 3 sin t)<br />

− (cos t − 2 sint)(3 cost + 4 sin t) =<br />

= 8 cos 2 t − 6 sin t cost + 4 sintcost − 3 sin 2 t − 3 cos 2 t −<br />

− 4 sin t cost + 6 sintcost + 8 sin 2 t = 8 − 3 = 5<br />

¸si solut¸iile sunt date <strong>de</strong>:<br />

˙C2 = − 4<br />

5 · et (cos t − 2 sint)<br />

˙ C3 = 4<br />

5 · et (−2 cos t − sin t).

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