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u perspek - Filozofski fakultet u Splitu

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cionalnog imperativa sljedeći:<br />

ρ =<br />

[<br />

r∈{1,...,n}<br />

{hwr,prijei} × ex(ρ, wr)<br />

∗∗∗<br />

h<br />

hρ, Resi [·¬nf(wi)] ⊕hρ, Resi ·nf(wi); ! > i<br />

ex(ρ, wi) =<br />

= hρ ∩k¬nf(wi)/>k . ∪ .ρ ∩knf(wi)/ex(ρ, wi)k ,Resi<br />

∗∗∗<br />

ρ ∩k¬nf(wi)/>k . ∪ .ρ ∩knf(wi)/ex(ρ, wi)k =<br />

⎛<br />

= ⎝ ρ ∩ Init−{hwi,prijei} ⎞<br />

× Res<br />

∪<br />

⎠<br />

ρ ∩{hwi,prijei} × ex(ρ, wi)<br />

⎛ [<br />

⎞<br />

{hwa,prijei} × Res<br />

⎜<br />

⎟<br />

= ⎜ a∈{1,...,n}−{i}<br />

⎟<br />

⎝ ∪<br />

⎠<br />

{hwi,prijei} × ex(ρ, wi)<br />

⎛ [<br />

⎞<br />

{wa,prije}×Res<br />

⎜ a∈{1,...,i−1}<br />

⎟<br />

= ⎜ ∪{wi,prije}×ex(ρ,<br />

[<br />

wi)∪ ⎟<br />

⎝<br />

{wb,prije}×Res<br />

⎠<br />

b∈{i,...,n}−{i}<br />

Time se lema potvr ¯duje za slučaj kada n 6= 1.<br />

Definicija 6.21 Funkcija s dodjeljuje rečenice za situaciju wi:<br />

½<br />

·> ako ex(ρ, wi) =π,<br />

s(wi) =<br />

·nf(wi) →! > nf(ex(ρ, wi))) ako ex(ρ, wi) ⊂ π.<br />

Lema 6.4<br />

96<br />

hmem1(ρ) × Res, Resi [s(w1); ...; s(wn)] = hρ, Resi

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