Practical Guige to Free Energy Devices

The result of this is that there is a backwards and forwards flow of static electricity along the earth connecting
wire, a flow which reverses direction sixty times per second. This is not conventional electricity but is the same
form of electricity which is collected by an aerial. Nikola Tesla’s patents show many different ways of utilising this
static electricity, as does Herman Plauson in his patent (www.free-energy-info.com/Chapter7.pdf). Thomas Henry
Moray produced fifty kilowatts of continuous power from quite a small aerial. Paul Baumann of the Swiss
commune produced several kilowatts from static electricity. Lorrie Matchett settles for just a few watts and he
does it like this:
He connects the live wire of a 110V (RMS) AC mains supply to a brass rod 28-inches (710 mm) long and 3/16
inches (4.76 mm) in diameter. The rod is not directly connected to anything else and so does not form part of a
closed loop circuit and so, no current flows from the mains. It must be stressed that the rod and connecting wire
are potentially very dangerous and need to be insulated very carefully to ensure that touching them will not cause
an electric shock. Please understand very clearly that as no current of any kind is drawn from the mains that this
circuit is not “stealing electricity from the mains”.
For convenience, and only for convenience, Lorrie uses the earthing system of the house mains supply by
connecting a green earthing wire to the earth pin of his mains plug. It needs to be clearly understood that this has
nothing directly to do with the mains supply and any good quality separate earth would be at least as good as the
earthing point inside the mains plug. Effectively, there is only one mains connection.
Instead of using a metal sphere as shown in the illustrations above, Lorrie uses a coil of wire wound around the
insulation layer on his brass rod, and he passes the alternating flow of static electricity, drawn from the earth,
through a standard diode bridge as shown here:
Lorrie covers the brass rod with insulation which is as thin as possible. He suggest heat-shrink tubing for the
insulation and on top of it he winds 0.405 mm diameter, solid-core enamelled copper wire, covering a 24-inch
(610 mm) length of the rod, placing the turns closely side by side and leaving 2-inches (50 mm) clear at each end
of the rod. Thicker wire should not be used.
He also shows a 500 milliamp fuse in the mains supply line. I am not at all happy about that as that fuse can
power five incandescent 100-watt mains bulbs connected in parallel, and do you really want that amount of power
flowing through you if your insulation is not good enough and you touch it? If you use a fuse in that position I
would suggest a 20 mm glass quick-blow 100 mA fuse (mainly because no smaller one is readily available). The
fuse is not needed for the circuit and is there in an attempt to protect careless humans.
The coil wound on the insulated brass rod is only connected at one end and that end goes to one of the two
“Alternating Current” tags on a 3A diode bridge. Lorrie does not specify the voltage rating for the diode bridge, but
it needs to be a minimum of 170-volts if the mains is a 110V (RMS) type, and double that for a 220V (RMS) mains
connection. I have no idea why he specifies a 3-amp rating, but the minimum bridge available locally at 3-amps
which I would recommend is a 400V rated unit which is supplied at trivial cost.
We need to understand the effect of the diode bridge. It halves the available voltage and doubles the frequency
as illustrated here:
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