Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR1 188 = 2 2 × 3 3 × 11-26. 3 887-21. 2 401507 = 3 × 13 2-16. 5293 887 = 13 2 × 232 401 = 7 4-27. 5 753-22. 2 093529 = 23 2-17. 6865 753 = 11 × 5232 093 = 7 × 13 × 23-28. 5 887686 = 2 × 7 3-23. 2 890-18. 8615 887 = 7 × 29 2-29. 9 410-19. 906861 = 7 × 3 × 41-24. 3 2492 890 = 2 × 5 × 17 2-30. 12 7409 410 = 2 × 5 × 941906 = 2 × 3 × 1513 249 = 3 2 × 19 2-20. 1 188-25. 3 703-31. 13 69012 740 = 2 2 × 5 × 7 2 × 133 703 = 7 × 23 2LEONARDO F. APALA TITO 104
SOLUCIONARIO DE ARITMETICA DE BALDORLos divisores:-32. 15 70013 690 = 2 × 5 × 37 2-37. 208 53748 763 = 11 2 × 13 × 31-2. 162162 = 2 × 3 4Número de divisores:(1 + 1)(4 + 1) = 2 × 5 = 10Los divisores:208 537 = 7 × 31 315 700 = 2 2 × 5 2 × 157-38. 327 701-33. 20 677-3. 150-34. 21 90120 677 = 23 × 29 × 31-39. 496 947327 701 = 11 × 31 3150 = 2 × 3 × 5 2Número de divisores:(1 + 1)(1 + 1)(2 + 1)2 × 2 × 3 = 12Los divisores:21 901 = 11 2 × 181-35. 47 60147 601 = 3 3 × 41 × 43-36. 48 763EJERCICIO 84496 947 = 3 × 11 2 × 37 2Hallar todos los divisores simples ycompuestos de los números siguientes,hallando primero el número de divisiones:-1. 5454 = 2 × 3 3Número de divisores:(1 + 1)(3 + 1) = 2 × 4 = 8-4. 1 0291 029 = 3 × 7 3Número de divisores:(1 + 1)(3 + 1) = 2 × 4 = 8Los divisores:LEONARDO F. APALA TITO 105
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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