Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
-3.
-4.
-5.
-6.
-7.
-8.
-9.
-10.
-11.
-12.
5 1 4 × 2 2 9 = 21
4 × 20
9
7 × 5
3
= 35
3 = 11 2 3
=
21 × 20
4 × 9
6 2 7 × 1 3 11 = 44
7 × 14
11
44 × 14
7 × 11 = 4 × 2 = 8
3 1 6 × 2 4 19 = 19
6 × 42
19 = 7
8 1 9 × 1 2 73 = 73
9 × 75
73 = 25
3 = 8 1 3
14 4 5 × 5 5 6 = 74
5 × 35
6 = 37 × 7
3
259
3 = 86 1 3
1 1 2 × 1 1 3 × 1 1 5 = 3 2 × 4 3 × 6 5
2 × 6
= 12
5 5 = 2 2 5
2 5 6 × 3 3 4 × 1 1 17 = 17
6 × 15
4 × 18
17
5 × 9
2 × 2 = 45
4 = 11 1 4
9 2 9 × 1 1 83 × 2 3 21 = 83
9 × 84
83 × 45
21
4 × 5 = 20
8 1 3 × 5 1 4 × 1 3 25 = 25
3 × 21
4 × 28
25
7 × 7 = 49
10 1 10 × 3 1
101 × 1 3
152
-13.
101
10 × 304
101 × 155
152 = 2 × 31
2
= 31
1 1 5 × 1 1 9 × 1 1 8 × 1 3 5 = 6 5 × 10
9 × 9 8 × 8 5
-14.
-15.
6 × 2
= 12
5 5 = 2 2 5
2 1 7 × 2 4 5 × 3 1 3 × 4 1 2
15
7 × 14
5 × 10
3 × 9 2 = 2 × 5 × 9 = 90
3 1 4 × 1 1 3 × 1 11
26 × 1 1 37
13
4 × 4 3 × 37
26 × 38
37 = 38
3 × 2 = 19
3 = 6 1 3
-16.
-17.
-18.
6 1 3 × 2 1 4 × 3 1 5 × 2 1 19
19
3 × 9 4 × 16
5 × 39
19 = 3 × 4 × 39
5
468
5 = 93 3 5
1 2 7 × 1 5 9 × 2 1 6 × 2 4 7
9
7 × 14
9 × 13
6 × 18
7 = 2 × 13 × 3
7
42
5 × 18
7 × 64
-19.
78
7 = 11 1 7
8 2 5 × 2 4 7 × 7 1 9 × 2 7 10
9 × 27
10
10 368
= 414 18
25 25
=
6 × 2 × 32 × 27
5 × 5
8 8 7 × 1 47
108 × 3 33
61 × 15 1 2 × 1 19
31
64
7 × 155
108 × 216
61 × 31
2 × 50
31
-20.
65 × 155 × 2 × 25
7 × 61
496000 253
= 1 161
427 427
2 4 39 × 2 1 6 × 1 1 41 × 4 1 3 × 2 4 7
EJERCICIO 135
Simplificar:
-1.
-2.
-3.
82
39 × 13
6 × 42
41 × 13
3 × 18
7
2 × 13 × 6
= 52
3
3 × 1 3 × 3 5 = 3 5
2 1 2 × 1 5 × 2 = 5 2 × 1 5 × 2 = 1
3 1 4 × 2 13 × 1 3 = 13
4 × 2 13 × 1 3 = 1
2 × 3 = 1 6
-4.
-5.
-6.
5
6 × 9 7 × 2 1 3 = 5 6 × 9 7 × 7 3
5 × 3
= 5 6 2 = 2 1 2
1 1 2 × 1 2 3 × 6 35 = 3 2 × 5 3 × 6 35 = 3 7
7
9 × 2 1 4 × 18
35 = 7 9 × 9 4 × 18
35 = 9
2 × 5 = 9 10
-7.
-8.
-9.
11
12 × 24 × 7
121 = 2 × 7
11 = 14
11 = 1 3 11
5
9 × 7 8 × 4 1 3 × 4 35 = 5 9 × 7 8 × 13
3 × 4 35
13
9 × 2 × 3 = 13
54
LEONARDO F. APALA TITO 163