Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR-14. 343.44121388-15. 512.76838407EJERCICIO 238Hallar la raíz cubica de:-1. 8273√ 8 273= √83= 2√27 3-2. 641253√ 641253= √64 = 4 3√125 5-3. 3432163√ 3432163= √3433= 7√216 6 = 1 1 6LEONARDO F. APALA TITO 292
SOLUCIONARIO DE ARITMETICA DE BALDOR-4. 243433√ 243433= √24√343= √23 ∙ 33 73= 2 37 √33√ 6861 7283= √686 =3√1 728O también:3√2 ∙ 7312= 7 312 √23√24O también:3= 2√343 7 con error < 1 7-10.1602 1973√6863= 8√1 728 12 = 2 3 con error < 1 123-5. √ 2505123√ 1602 1973= √160√2 1973= √23 ∙ 22 ∙ 53 13= 2√4 3∙ 5 = 2 313 13 √203√ 2505123= √2503=√5123√2 ∙ 538O también:= 5 38 √23√160O también:= 5 3√2 197 13 con error < 1 133√2503= 6√512 8 = 3 4 con error < 1 8-11.242 7443-6. √ 327293√ 242 7443= √243 √2 744= √23 ∙ 3143= 2√3314 = 1 37 √33√ 327293= √32√729= √23 ∙ 223 93= 2 39 √22= 2 39 √43√24O también:3= 2√2 744 14 = 1 7 con error < 1 14O también:-12.1252 197-7.3751 0003√32= 3 3√729 9 = 1 3 con error < 1 9-13.543 3753√ 1252 1973= √125 = 5 3√2 197 13-8.541 3313√ 3751 0003= √3753=√1 0003√3753√3 ∙ 5310O también:= 5√3310 = 1 32 √3= 7 3√1 000 10 con error < 1 10-14.1284 0963√ 543 3753= √543=√3 3753√543√2 ∙ 3315O también:= 3√2315 = 1 35 √23= 3√3 375 15 = 1 5 con error < 1 5-9.6861 7283√ 541 3313√543= √543=√1 331O también:3√2 ∙ 3311= 3 311 √2= 3 3√1 331 11 con error < 1 11-15.3√ 1284 0963758 0003= √1283 √4 096= √26 ∙ 2163√1283O también:= 22 3√2= 5 3√4 096 16 con error < 1 16316 = 4√216 = 1 34 √2LEONARDO F. APALA TITO 293
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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