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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR

-10. 9/22 a 176avos

8

21 = 8 × 5

21 × 5 = 40

105

9

22 = 9 × 8

22 × 8 = 72

176

-11. 24/25 a 200avos

24

25 = 24 × 8

25 × 8 = 192

200

-12. 23/26 a 104avos

23

26 = 23 × 4

26 × 4 = 92

104

-13. 33/29 a 174avos

33

29 = 33 × 6

29 × 6 = 198

174

-14. 79/83 a 415avos

79

83 = 79 × 5

83 × 5 = 345

415

-15. 9/114 a 798avos

9

114 = 9 × 7

114 × 7 = 63

798

-16. 1/11 a 1 331avos

1

11 = 1 × 121

11 × 121 = 121

1 331

-17. 3/13 a 1 690avos

3

13 = 3 × 130

13 × 130 = 390

1 690

-18. 5/23 a 5 290avos

5

23 = 5 × 230

23 × 230 = 1 150

5 290

-19. 7/29 a 841avos

7

29 = 7 × 29

29 × 29 = 203

841

-20. 11/31 a 9 610avos

EJERCICIO 109

Reducir:

11 11 × 310

=

31 31 × 310 = 3 410

9 610

-1. 11/76 a quebrado equivalente de

denominador 684.

11

76 = 11 × 9

76 × 9 = 99

684

-2. 7/65 a quebrado equivalente de

denominador 520.

7

65 = 7 × 8

65 × 8 = 56

520

-3. 13/72 a quebrado equivalente de

denominador 576.

13

72 = 13 × 8

72 × 8 = 104

576

-4. 7/81 a quebrado equivalente de

denominador 729.

7

81 = 7 × 9

81 × 9 = 63

729

-5. 11/91 a quebrado equivalente de

denominador 637.

11

91 = 11 × 7

91 × 7 = 77

637

-6. 7/94 a quebrado equivalente de

denominador 752.

7

94 = 7 × 8

94 × 8 = 56

752

-7. 13/98 a quebrado equivalente de

denominador 882.

13

98 = 13 × 9

98 × 9 = 117

882

-8. 7/102 a quebrado equivalente de

denominador 816.

7

102 = 7 × 8

102 × 8 = 56

816

-9. 113/123 a quebrado equivalente de

denominador 1 107.

113

123 = 113 × 9

123 × 9 = 1 017

1 107

-10. 7/12 a quebrado equivalente de

denominador 1 296.

7

12 = 7 × 108

12 × 108 = 756

1 296

-11. 5/18 a quebrado equivalente de

denominador 3 600.

5

18 = 5 × 200

18 × 200 = 1 000

3 600

-12. 19/23 a quebrado equivalente de

denominador 1 058.

19 19 × 46

=

23 23 × 46 = 874

1 058

-13. 32/41 a quebrado equivalente de

denominador 3 690.

32 32 × 90

=

41 41 × 90 = 2 880

3 690

-14. 7/81 a quebrado equivalente de

denominador 7 290.

EJERCICIO 110

7

81 = 7 × 90

81 × 90 = 630

7 290

Reducir, por simple inspección:

-1. 2 4 = 2

-2. 4 6 = 3

-3. 4 8 = 2

-4. 6

10 = 5

-5. 9

24 = 8

-6. 10

18 = 9

-7. 15

20 = 4

-8. 16

20 = 5

-9. 8

22 = 11

-10. 32

24 = 3

2

4 = 2 ÷ 2

4 ÷ 2 = 1 2

4

6 = 4 ÷ 2

6 ÷ 2 = 2 3

4

8 = 4 ÷ 4

8 ÷ 4 = 1 2

6

10 = 6 ÷ 2

10 ÷ 2 = 3 5

9

24 = 9 ÷ 3

24 ÷ 3 = 3 8

10

18 = 10 ÷ 2

18 ÷ 2 = 5 9

15

20 = 15 ÷ 5

20 ÷ 5 = 3 4

16

20 = 16 ÷ 4

20 ÷ 4 = 4 5

8

11 = 8 ÷ 2

22 ÷ 2 = 4 11

LEONARDO F. APALA TITO 139

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