Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
1 min → 2 3 ÷ 20 = 2 3 × 1 20 = 1
3 × 10
= 1 30 pag
Empleara en estudiar 10 páginas
10 ÷ 1 = 10 × 30 = 300 min
30
300 min × 1 hora
60 min = 5 h
-14. ¿Entre que numero hay que dividir 6
2/ 5 para obtener 3 de cociente?
R. Sea en número: “N”
6 2 32 32
5
N = 3 → 5
N = 3 → 5
3 = N
N = 32
5 ÷ 3 = 32
5 × 1 3 = 32
15 = 2 2 15
-15. Repartí $18 2/ 5 entre varias personas
y a cada una toco $3 17/ 25. ¿Cuántas
eran las personas?
R.
EJERCICIO 145
Simplificar:
-1.
-2.
-3.
-4.
-5.
18 2 5 ÷ 3 17
25 = 92
5 ÷ 92
25
92
5 × 25
92 = 25
5 = 5
5
= 5 ÷ 3 3 8 = 5 × 8 3 = 40
3 = 13 1 3
8
7
8
10 = 7 8 ÷ 10 = 7 8 × 1 10 = 7 80
3⁄
5
1⁄
10
= 3 5 ÷ 1 10 = 3 5 × 10 = 6
2⁄
3
3⁄ 7
= 2 3 ÷ 3 7 = 2 3 × 7 3 = 14
9 = 1 5 9
4 1⁄
3
6 1⁄ = 4 1 3 ÷ 6 1 3 = 13
3 ÷ 19
3
3
-6.
13
3 × 3 19 = 13
19
2⁄
19
6 4⁄ = 2 19 ÷ 6 4 5 = 2 19 ÷ 34
5 = 2 19 × 5 34
5
5
=
19 × 17 = 5
323
-7.
-8.
-9.
5⁄
8
3⁄
16
= 5 8 ÷ 3 16 = 5 8 × 16
3
5 × 2
= 10
3 3 = 3 1 3
7 3⁄
4
= 7 3 1⁄
8 4 ÷ 1 8 = 31
4 ÷ 1 8 = 31
4 × 8
= 31 × 2 = 62
5
= 5 ÷ 1
1 1⁄ 2
= 5 ÷ 2 = 5 2 = 2 1 2
1⁄
2
-10.
-11.
-12.
-13.
-14.
15
= 15 ÷ 1
1 1⁄ = 15 ÷ 4 = 3 1 2
1 4
⁄ 4
16
= 16 ÷ 1
1 1⁄ = 16 ÷ 4 = 4
1 4
⁄ 4
1
1⁄
5
15 = 5 15 = 1 3
1
5 6
⁄ 6
15 = 5
15 = 6 5 ÷ 15 = 6 5 × 1 15
1
3⁄
5
1
3⁄
8
=
2
5 × 5 = 2 25
5
3
= 5 8 3 ÷ 8 3 = 5 3 × 3 8 = 5 8
3
-15.
1
5 3⁄
4
=
1
4 1⁄ 5
-16.
-17.
3
3⁄
4
1
1⁄
6
1
23⁄
4
=
1
21⁄
5
4
23
= 4 5 23 ÷ 5 21
21
= 4 23 × 21
5 = 84
115
= 3 ÷ 3 4
1 ÷ 1 = 3 × 4 3
= 4 6 6 = 2 3
6
6
5⁄
8
= 6 ÷ 5 8
= 6 × 8 5
3⁄
3 5 5 ÷ 2 3
5 × 1 2
2
-18.
2⁄
3
3⁄
5
=
1⁄
6
2⁄
5
-19.
-20.
5 2⁄
3
1⁄
4
6 1⁄
2
1⁄
6
1⁄
3
4 1⁄
5
1⁄
2
=
48
5
= 48
3 5 ÷ 3 10
10
48
5 × 10 = 16 × 2 = 32
3
2
3 ÷ 3 5
1
6 ÷ 2 =
5
2
3 × 5 3
1
6 × 5 =
2
10
9
= 10
5 9 ÷ 5 12
12
10
9 × 12
5 = 2 × 4 = 8 3 3 = 2 2 3
=
=
3 2⁄ 5
17⁄
3
1⁄
4
13⁄
2
1⁄
6
=
17
3 ÷ 1 17
4
13
2 ÷ 1 =
3 × 4
13
6 2 × 6
68 68
3
13 × 3 = ⁄ 3
39 = 68
3 ÷ 39
68
3 × 1 39 = 68
117
1
3 ÷ 4 1 5
1
2 ÷ 3 2 =
5
1
3 ÷ 21
5
1
2 ÷ 17 =
5
1
3 × 5 21
1
2 × 5 17
5
63
= 5 5 63 ÷ 5 34 = 5 63 × 34
5 = 34
63
34
LEONARDO F. APALA TITO 173