Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR-7. 1 8Fracción decimal: periódica pura-16. 105140-12. 4 5Fracción decimal: exactaFracción decimal: exacta-13. 512Fracción decimal: exacta-17.1500-8.19Fracción decimal: exacta-18.1333Fracción decimal: periódica pura-9. 2 5Fracción decimal: periódica mixta-14. 711Fracción decimal: exactaFracción decimal: periódica pura-10. 3 5-19.6111Fracción decimal: exacta-11. 2 3Fracción decimal: periódica pura-15. 2496Fracción decimal: periódica puraFracción decimal: exacta-20. 13740LEONARDO F. APALA TITO 226
SOLUCIONARIO DE ARITMETICA DE BALDORFracción decimal: periódica mixtaEJERCICIO 182Decir qué clase de fracciones decimalesson las siguientes:-1. 0.04Fracción decimal: exacta-2. 0.777Fracción decimal: periódica pura-3. 0.1333Fracción decimal: periódica mixta-4. 0.1717Fracción decimal: periódica pura-5. 0.005Fracción decimal: exacta-6. 0.178178Fracción decimal: periódica pura-7. 0.45111Fracción decimal: periódica mixta-8. 0.1981616Fracción decimal: periódica mixta-9. 0.0767Fracción decimal: exacta-10. 0.001818Fracción decimal: periódica mixta-11. 0.765765Fracción decimal: periódica pura-12. 0.00303Fracción decimal: periódica mixta-13. 0.12341234Fracción decimal: periódica pura-14. 0.0109898Fracción decimal: periódica mixta-15. 2.654886Fracción decimal: inexacta no periódica-16. 3.33345345Fracción decimal: periódica mixta-17. 0.000111Fracción decimal: periódica mixta-18. 0.03390972Fracción decimal: inexacta no periódica-19. 0.99102557Fracción decimal: inexacta no periódica-20. 9.78102793Fracción decimal: inexacta no periódicaEJERCICIO 183Simplificar, convirtiendo los quebradoscomunes en decimales:-1.-2.12 + 1 834 − 1 8Se tiene: 1/ 2 = 0.5; 1/ 8 = 0.125;3/ 4 = 0.750.5 + 0.1250.75 − 0.125 = 0.6250.625 = 178 + 5 2 5 − 1 1 41 1 10 + 2 3 5 − 1 3 16Se tiene: 7/ 8 = 0.875;5 2/ 5 = 27/ 5 = 5.4;1 1/ 4 = 5/ 4 = 1.25;1 1/ 10 = 11/ 10 = 1.1;-3.-4.-5.-6.2 3/ 5 = 13/ 5 = 2.6;1 3/ 16 = 19/ 16 = 1.18750.875 + 5.4 − 1.251.1 + 2.6 − 1.1875 = 5.0252.5125 = 215 + 0.166 + 9125110 + 77100 + 3500Se tiene: 1/ 5 = 0.2; 9/ 125 = 0.072;1/ 10 = 0.1;77/ 100 = 0.77;3/ 500 = 0.0060.2 + 0.166 + 0.0720.1 + 0.77 + 0.006 = 0.4380.876 = 0.5( 7 20 + 1 50 ) + 3 3 4( 4 5 + 7 10 ) + 3 7 10Se tiene: 7/ 20 = 0.35; 1/ 50 = 0.02;3 3/ 4 = 15/ 4 = 3.75; 4/ 5 = 0.8;7/ 10 = 0.7; 3 7/ 10 = 37/ 10 = 3.7(0.35 + 0.02) + 3.75 0.37 + 3.75=(0.8 + 0.7) + 3.7 1.5 + 3.7= 4.125.2 = 0.792( 9 50 + 1 1925 − 1500 ) ÷ 1500( 1 8 + 27250 + 9100 ) ÷ 11 000Se tiene: 9/ 50 = 0.18;1 19/ 25 = 44/ 25 = 1.76;1/ 500 = 0.002; 1/ 8 = 0.125;27/ 250 = 0.108; 9/ 100 = 0.09;1/ 1000 = 0.001(0.18 + 1.76 − 0.002) ÷ 0.002(0.125 + 0.108 + 0.09) ÷ 0.0011.938 ÷ 0.0020.323 ÷ 0.001 = 969323 = 3LEONARDO F. APALA TITO 227
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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