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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR

9 072.08109 km 3

= 9 072 km 3 81 hm 3 90 dam 3

-18. 6 754 327.0060572 dam 3

89 306.054 km 2

= 89 306 km 2 5 hm 2 40 dam 2

-11. 1 803.05 hm 3

1 056.00432 hl

= 105 kl 6 hl 4 dl 3 cl 2 ml

-26. 0.00356 Qm

6 754 327.0060572 dam 3

= 6 km 3 754 hm 3 327 dam 3 6 m 3 57 dm 3 200 cm 3

-19. 23.0040056 dm 3

23.0040056 dm 3

= 23 dm 3 4 cm 3 5.6 mm 3

-20. 1 234.7645 cm 3

1 234.7645 cm 3

= 1 dm 3 234 cm 3 764.5 mm 3

EJERCICIO 255

MISCELANEA

Reducir a denominador:

-1. 145.03 dam

145.03 dam

= 1 km 4 hm 5 dam 3 dm

-2. 1 324 Qm

-3. 116 ha

-4. 1 603 m 3

1 324 Qm = 132 Tm 4 Qm

116 ha = 1 km 2 16 ha

1 603 m 3 = 1 dam 3 603 m 3

-5. 456.89 dm

456.89 dm

= 4 dam 5 m 6 dm 8 cm 9 mm

-6. 189.003 dag

189.003 dag = 1 kg 8 hg 9 dag 3 cg

-7. 108.0035 ca

108.0035 ca = 1 a 8 ca 35 cm 2

-8. 1 803 564 dam 3

1 803 564 dam 3

= 1 km 3 803 hm 3 564 dam 3

-9. 0.0001 m

0.0001 m = 0.1 mm

-10. 89 306.054 km 2

1 803.05 hm 3

= 1 km 3 803 hm 3 50 dam 3

-12. 12 340.56 kl

12 340.56 kl = 12 340 kl 5 hl 6 dal

-13. 89 325 m 2

89 325 m 2 = 8 hm 2 93 dam 2 25 m 2

-14. 0.56896 Tm

0.56896 Tm

= 5 Qm 68 kg 9 hg 6 dag

-15. 0.00013 hm 2

0.00013 hm 2 = 1 m 2 30 dm 2

-16. 19 035.6543 km 3

19 035.6543 km 3

= 19 035 km 3 654 hm 3 300 dam 3

-17. 980.03 km

980.03 km = 980 km 3 dam

-18. 1 890.00003 a

1 890.00003 a = 18 ha 90 a 30 cm 2

-19. 186 432.007 ha

186 432.007 ha

= 1 864 km 2 32 ha 70 ca

-20. 0.0010325 m 3

0.0010325 m 3

= 1 dm 3 32 cm 3 500 mm 3

-21. 0.0013 dm 3

0.0013 dm 3 = 1 cm 3 300 mm 3

-22. 1 403.564 kg

1 403.564 kg

= 1 Tm 4 Qm 3 kg 5 hg 6 dag 4 g

-23. 10 035.05643 a

10 035.05643 a

= 1 km 2 35 a 5 ca 64 dm 2 30 cm 2

-24. 0.05 cm 3

0.05 cm 3 = 50 mm 3

-25. 1 056.00432 hl

0.00356 Qm = 3 hg 5 dag 6 g

-27. 188 643 253.0056 m 3

188 643 253.0056 m 3

= 188 hm 3 643 dam 3 253 m 3 5 dm 3 600 cm 3

-28. 285 3 4 dam

285 3 dam = 285.75 dam

4

285.75 dam

= 2 km 8 hm 5 dam 7 m 5 dm

-29. 1 008 7

10 a

1 008 7 a = 1 008.7 a

10

1 008.7 a = 10 ha 8 a 70 ca

-30. 234 3 5 m3

234 3 5 m3 = 234.6 m 3

234.6 m 3 = 234 m 3 600 dm 3

-31. 12 345 1 8 dam3

12 345 1 8 dam3 = 12 345.125 dam 3

12 345.125 dam 3

= 12 hm 3 345 dam 3 125 m 3

-32. 7 654 329 7

20 ha

7 654 329 7 ha = 7 654 329.35 ha

20

7 654 329.35 ha

= 76 543 km 2 29 ha 35 a

-33. 1 008 9

16 ca

1 008 9 ca = 1 008.5625 ca

16

1 008.5625 ca

= 10 a 8 ca 56 dm 2 25 cm 2

-34. 8 1 kl 2

8 1 kl = 8.5 kl

2

8.5 kl = 8 kl 5 hl

LEONARDO F. APALA TITO 328

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