Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR-31. 2 meses 15 días 16 segundos adías30 dias2 meses = 2 meses ×1 mes= 60 diasSumando: 60 días + 15 días = 75 días16 seg × 1 min60 seg × 1 hora60 min × 1 dia24 horas= 15 400 diaSumando:75 dias + 11dia = 755400 5400 dias-32. 2 años 20 dias 24 min a meses12 meses2 años = 2 años ×1 año= 24 meses20 dias = 20 dias × 1 mes30 dias = 2 3 mes24 min= 24 min × 1 hora60 min × 1 dia24 horas × 1 mes30 diasSumando:= 11 800 mes24 meses + 2 3 mes + 11 800 mes1 200 meses + 1 mes24 meses +1 80024 mese + 1 2011 800 meses24 1 2011 800 meses-33. 8 meses 8 horas 8 minutos 8segundos a meses60 min8 horas = 8 horas ×1 hora= 480 minSumando: 480 min + 8 min = 488 min60 seg488 min = 488 min ×1 min= 29 280 segSumando: 29 280 seg + 8 seg = 29 288 seg29 288 seg= 29 288 seg × 1 min60 seg × 1 hora60 min × 1 dia24 horas× 1 mes30 diasSumando:= 3661324 000 meses8 meses + 3 661324 000 mesesEJERCICIO 2808 3 661324 000 mesesReducir a denominado:-1. 121 207 s121 207 s = 1 d 9 h 40 min 7 s-2. 8 197 días8 197 dias = 2 dec 2 a 9 m 7 d-3. 19 123 lb19 123 lb = 9 T 11 qq 23 lb-4. 873 @873 @ = 10 T 18 qq 1 @-5. 186 931 ad186 931 ad = 7 qq 1@ 5 lb 3 oz 3 ad-6. 50 131’’ S50 131 ′′ S = 13 o 55 ′ 31 ′′ S-7. 563 pulg563 pulg = 15 v 1 pie 11 pulg-8. 37 932 ozLEONARDO F. APALA TITO 372
SOLUCIONARIO DE ARITMETICA DE BALDOR-14. 3 154’’ C1 901 ′ S = 31 o 41 ′ S37 932 oz = 1 T 3 qq 2 @ 20 lb 12 oz-9. 1 097 h-10. 1 201 lin1 097 h = 1 m 15 d 17 h1 201 lin = 2 v 2 pies 4 pulg 1 lin-11. 517 años517 a= 5 siglos 1 dec 1 lustro 2 años-12. 10 800 puntos-13. 1 901’ S3 154 ′′ C = 31 ′ 54 ′′ C-15. 123 104’’ C123 104 ′′ C = 12 o 31 ′ 4 ′′ C-16. 3 410 yardas3 410 yardas = 1 mill. 7 furl. 20 pol.-17. 20 318’’ S20 318 ′′ S = 5 o 38 ′ 38 ′′ S-18. 180 180 pulg ing180 180 pulg ing= 2 mill. 6 furl. 30 pol.EJERCICIO 281Reducir a denominador o valuar:-1. 1 de hora7Luego:17 hora = 1 7 × 60 min = 8 4 7 min4de min747 min = 4 240× 60 s =7 7 s = 34 2 7 sSiendo:-2. 8de año1117 de hora = 8 min 34 2 7 s811 año = 8 36× 12 meses =11 11 mesesLuego:= 3 3 11 meses311 meses = 3 90× 30 d =11 11 d = 8 2 11 dLuego:211 d = 2 48× 24 h =11 11 h = 4 4 11 hLuego:LEONARDO F. APALA TITO 373
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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