Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDORAhora:1 Tm145.32 g ×1 000 000 g × 1 m31 Tm= 0.00014532 m 3-7. 1 834.563 m 3 a lSiendo: 1 m 3 = 1 000 dm 3También: 1 dm 3 = 1 lAhora:1 834.563 m 3 1 000 dm3×1 m 3 × 1 l1 dm 3= 1 834 563 l-8. 165 cm 3 a lSiendo: 1 dm 3 = 1 000 cm 3También: 1 dm 3 = 1 lAhora:165 cm 3 × 1 dm31 000 cm 3 × 1 l1 dm 3= 0.165 l-9. 12.356 dm 3 a mlSiendo: 1 dm 3 = 1 000 cm 3También: 1 cm 3 = 1 mlAhora:12.356 dm 3 1 000 cm3×1 dm 3 × 1 ml1 cm 3= 12 356 ml-10. 20.345 l a gSiendo: 1 l = 10 dl = 100 cl = 1 000 mlTambién: 1 ml = 1 gAhora:20.345 l ×-11. 116.35 kl a kgSiendo: 1 kl = 1 000 lTambién: 1 l = 1 kgAhora:1 000 ml× 1 g = 20 345 g1 l 1 ml1 000 l116.35 kl × × 1 kg1 kl 1 l= 116 350 kg-12. 20 356.4 dm 3 a gSiendo: 1 dm 3 = 1 000 cm 3También: 1 cm 3 = 1 gAhora:20 356.4 dm 3 1 000 cm3×1 dm 3 × 1 g1 cm 3= 20 356 400 g-13. 8.65 m 3 a kgSiendo: 1 m 3 = 1 000 dm 3También: 1 dm 3 = 1 kgAhora:8.65 m 3 1 000 dm3×1 m 3 × 1 kg1 dm 3= 8 650 kg-14. 1 kg a cm35Siendo: 1 kg = 1 000 gTambién: 1 g = 1 cm 3Ahora:1 1 000 gkg ×5 1 kg × 1 cm31 g-15. 2 l a Tm3Siendo: 1 kl = 1 000 lTambién: 1 kl = 1 TmAhora:= 200 cm 3=1 000 cm352 1 kll ×3 1 000 l × 1 Tm1 kl = 23 000 Tm= 0.00067 Tm-16. 1 8 m3 a gSiendo:1 m 3 = 1 000 dm 3 = 1 000 000 cm 3También: 1 cm 3 = 1 gAhora:1 1 000 000 cm38 m3 ×1 m 3 × 1 g1 cm 31 000 000 g8-17. 2 5 cm3 a l= 125 000 gSiendo: 1 dm 3 = 1 000 cm 3También: 1 dm 3 = 1 lAhora:25 cm3 × 1 dm31 000 cm 3 × 1 l1 dm 3 = 25 000 l= 0.0004 l-18. 8 1 g a dm35Siendo: 1 kg = 1 000 gTambién: 1 kg = 1 dm 3Ahora:8 1 5g ×1 kg1 000 g × 1 dm31 kg = 8.21 000 dm3-19. 2 1 Tm a ml5= 0.0082 dm 3Siendo: 1 Tm = 1 000 kg = 1 000 000 gTambién: 1 g = 1 mlAhora:2 1 51 000 000 gTm × × 1 ml1 Tm 1 g2.2 ml × 1 000 000 = 2 200 000 ml-20. 1 ml a dm32Siendo: 1 l = 1 000 mlTambién: 1 l = 1 dm 3Ahora:12 ml × 1 l1 000 ml × 1 dm3 = 11 l 2 000 dm3= 0.0005 dm 3-21. 1 kl a kg4Siendo: 1 kl = 1 000 lTambién: 1 l = 1 kgAhora:141 000 lkl × × 1 kg1 kl 1 l-22. 23 1 l a g6Siendo: 1 l = 1 000 mlTambién: 1 ml = 1 gAhora:= 1 000 kg4= 250 kgLEONARDO F. APALA TITO 340
SOLUCIONARIO DE ARITMETICA DE BALDOR23 1 61 000 mll × × 1 g1 l 1 ml23.167 g × 1 000 = 23 167 g-24. 563.2 kl a dm 3Siendo: 1 kl = 1 000 lTambién: 1 l = 1 dm 3Ahora:563.2 kl ×-25. 51.032 dag a m 31 000 l× 1 dm31 kl 1 l= 563 200 dm 3Siendo: 1 Tm = 1 000 kg = 10 000 hg= 100 000 dagTambién: 1 Tm = 1 m 3Ahora:1 Tm51.032 dag ×100 000 dag × 1 m31 Tm= 0.00051032 m 3-26. 1 142.003 mm 3 a hlSiendo:1 dm 3 = 1 000 cm 3 = 1 000 000 mm 3También: 1 dm 3 = 1 l y 1 hl = 100 lAhora:1 142.003 mm 3 1 dm 3×1 000 000 mm 3× 1 l1 dm 3 × 1 hl100 l=1 142.003 hl= 0.00001142003 hl100 000 000-27. 18 134 hg a hlSiendo: 1 kg = 10 hgTambién: 1 kg = 1 l y 1 hl = 100 l18 134 hg × 1 kg10 hg × 1 l1 kg × 1 hl100 l18 134hl = 18.134 hl1 000-28. 1 413.5 dg a clSiendo: 1 g = 10 dgTambién: 1 g = 1 mly 1 cl = 10 mlAhora:1 413.5 dg × 1 g10 dg × 1 ml1 g × 1 cl10 ml1 413.5cl = 14.135 cl100-29. 103.54 hm 3 a hgSiendo: 1 hm 3 = 1 000 dam 3= 1 000 000 m 3 = 1 000 000 000 dm 3También:Ahora:= 1 000 000 000 000 cm 31 cm 3 = 1 g y 1 hg = 100 g103.54 hm 3 1 000 000 000 000 cm3×1 hm 3× 1 g1 cm 3 × 1 hg100 g= 103.54 × 10 000 000 000 hg= 1 035 400 000 000 hg-30. 1 536 dl a QmSiendo: 1 l = 10 dlTambién:1 l = 1 kg y 1 Qm = 100 kgAhora:1 536 dl × 1 l10 dl × 1 kg1 l1 536Qm = 1.536 Qm1 000-31. 8 kg 6 dag a dm 31º: 8 kg 6 dag a kg× 1 Qm100 kg6 dag = 6 dag × 1 kg = 0.06 kg100 dagSumando: 8 kg + 0.06 kg = 8.06 kgDonde: 1 kg = 1 dm 3Ahora:8.06 kg × 1 dm31 kg-32. 15 hl 142 l a cm 31º: 15 hl 142 l a ml= 8.06 dm315 hl = 1 500 l = 1 500 000 ml142 l = 142 000 mlSumando: 1 500 000 ml + 142 000 ml= 1 642 000 mlDonde: 1 ml = 1 cm 31 642 000 ml × 1 cm31 ml-33. 16 hl 19 dl a hg1º: 16 hl 19 dl a ml= 1 642 000 cm316 hl = 1 600 l = 1 600 000 ml19 dl = 190 cl = 1 900 mlSumando: 1 600 000 ml + 1 900 ml= 1 601 900 mlDonde: 1 ml = 1 g y 1 hg = 100 gAhora:1 601 900 ml × 1 g1 ml × 1 hg100 g= 16 019 hg-34. 8 dam 3 14 m 3 6 cm 3 a dal1º: 8 dam 3 14 m 3 6 cm 3 a dm 38 dam 3 = 8 000 m 3 = 8 000 000 dm 314 m 3 = 14 000 dm 36 cm 3 = 6 cm 3 × 1 dm31 000 cm 3= 0.006 dm 3Sumando:8 000 000 dm 3 + 14 000 dm 3 + 0.006 dm 3= 8 014 000.006 dm 3Donde: 1 dm 3 = 1 l yAhora:1 dal = 10 l8 014 000.006 dm 3 × 1 l1 dm 3 × 1 dal10 l= 801 400.0006 dal-35. 140 kl 8 dal 16 cl a dag1º: 140 kl 8 dal 16 cl a ml140 kl = 140 000 l = 140 000 000 mlSumando:8 dal = 80 l = 80 000 ml16 cl = 160 mlLEONARDO F. APALA TITO 341
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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