Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
11 + 15 = 26
-7. (8 – 6) + (7 – 4)
2 + 3 = 5
-8. (9 + 5) + (7 – 2)
14 + 5 = 19
-9. 56 – (3 + 5 + 11)
56 − 19 = 37
-10. (8 + 7 + 4) – 16
19 − 16 = 3
-11. 89 – (56 – 41)
89 − 15 = 74
-12. (43 – 15) – 19
28 − 19 = 9
-13. (9 + 4 + 5) – (7 + 3 + 2)
18 − 12 = 6
-14. (11 – 5) – (9 – 3)
6 − 6 = 0
-15. (7 + 6) – (9 – 8)
13 − 1 = 12
-16. (11 – 5) – 4
6 − 4 = 2
-17. (9 – 4) + (3 + 2 + 5)
5 + 10 = 15
-18. (9 – 4) + (8 – 3)
5 + 5 = 10
-19. (85 – 40) – (95 – 80)
45 − 15 = 30
-20. (14 + 6 – 4) – (9 – 7 – 2)
16 − 0 = 16
-21. 450 – (14 – 6 + 5 – 4)
450 − 9 = 441
-22. (9 – 6 + 3) – 2 – (8 – 7 + 1)
6 − 2 − 2 = 4 − 2 = 2
-23. (14 + 5) – (6 – 4 + 3) + (6 – 4 + 2)
19 − 5 + 4 = 14 + 4 = 18
-24. 250 – (6 – 4 + 5) – 8 – (9 – 5 + 3)
250 − 7 − 8 − 7 = 243 − 8 − 7
= 235 − 7 = 228
-25. 300 – (5 – 2) – (9 – 3) + (5 – 4)
300 − 3 − 6 + 1 = 297 − 6 + 1
= 291 + 1 = 292
-26. (7 – 5) + (13 – 4) – (17 + 3) + (18 – 9)
2 + 9 − 20 + 9 = 20 − 20 = 0
-27. (15 – 7) + (6 – 1) – (9 – 6) + (19 + 8) –
(3 – 1) + (4 + 5)
8 + 5 − 3 + 27 − 2 + 9
13 − 3 + 27 − 2 + 9
10 + 27 − 2 + 9 = 37 − 2 + 9 = 44
-28. (13 – 5 + 6) – (21 + 2 – 18) + (7 – 5) –
(8 – 2 + 1)
14 − 5 + 2 − 7 = 9 + 2 − 7 = 4
-29. 350 – 2 – 125 + 4 – (31 – 30) – (7 – 1)
– (5 – 4 + 1)
227 − 1 − 6 − 2 = 218
-30. (8 – 1) – (16 – 9) + 4 – 1 + 9 – 6 +
(11 – 6) – (9 - 4)
7 − 7 + 3 + 3 + 5 − 5 = 3 + 3 = 6
EJERCICIO 34
Efectuar:
-1. 40 + [25 – (3 + 2)]
40 + (25 − 5) = 40 + 20 = 60
-2. 60 + [(4 + 2) - 5]
60 + (6 − 5) = 60 + 1 = 61
-3. 150 – [(5 – 1) – (4 – 3)]
150 − (4 − 1) = 150 − 3 = 147
-4. 250 + [(7 – 2) + (4 – 1) + (3 – 2)]
250 + (5 + 3 + 1) = 250 + 9 = 259
-5. 450 – [6 + {4 – (3 – 1)}]
450 − [6 + {4 − 2}] = 450 − [6 + 2]
= 450 − 8 = 442
-6. 520 + [8 – 3 + {9 – (4 + 2 – 1)}]
520 + [5 + {9 − 5}] = 520 + [5 + 4]
= 520 + 9 = 529
-7. (150 – 5) – {14 + (9 – 6 + 3)}
145 − {14 + 6} = 145 − 20 = 125
-8. 500 – {6 + [(14 – 6) – (7 – 2) + (4 – 1)]}
500 − {6 + [8 − 5 + 3]}
= 500 − {6 + 6}
= 500 − 12 = 488
-9. 500 – {14 - [7 – (6 – 5 + 4)]}
500 − {14 − [7 − 5]} = 500 − {14 − 2}
= 500 − 12 = 488
-10. 856 + {19 – 3 - [6 + (5 – 3) – (2 + 1) +
(5 – 3)]}
856 + {16 − [6 + 2 − 3 + 2]}
856 + {16 − 7} = 856 + 9 = 865
-11. [8 + (4 – 2)] + [9 – (3 + 1)]
[8 + 2] + [9 − 4] = 10 + 5 = 15
-12. [(6 – 4) – (3 – 2)] - [(9 – 7) – (6 – 5)]
[2 − 1] − [2 − 1] = 1 − 1 = 0
-13. 8 + [9 – {6 – (5 – 4)}] + 14 – {11 – [7 –
(3 – 2)]}
8 + [9 − {6 − 1}] + 14 − {11 − [7 − 1]}
8 + [9 − 5] + 14 − {11 − 6}
8 + 4 + 14 − 5 = 21
LEONARDO F. APALA TITO 38