Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
-14.
-15.
(7 2 9 + 5 1 6 − 12 5 18 ) × 27
( 2 9 + 1 6 − 5 18 ) × 27
( 4 + 3 − 5 ) × 27 = 2 18
18 × 27
1
9 × 27 = 3
2
3 × (10 1 4 × 1 16 ) × 2 1 40
2
3 × 41
4 × 1 16 × 81
40
41 × 27
2 × 16 × 40 = 1 107
1 280
(2 + 1 4 ) × (6 − 1 30 ) = 9 30
× (5
4 30 − 1 30 )
-16.
-17.
-18.
9
4 × 5 29
30 = 9 4 × 179
30
3 × 179
4 × 10 = 537
40
= 13
17
40
(2 − 1 4 ) × (6 + 1 30 )
(1 4 4 − 1 4 ) × 181
30 = 1 3 4 × 181
30
7
4 × 181
30 = 1 267
120
= 10
67
120
( 2 3 − 1 4 ) × (2 3 + 3 4 )
( 8 − 3
12 ) × (8 + 9
12 ) = 5 12 × 17
12 = 85
144
-20.
-21.
-22.
-23.
-24.
(11 1 10 − 10) × (13 − 9 2 5 )
1 1 10 × (12 5 5 − 9 2 5 ) = 11
10 × 3 3 5
11
10 × 18
5 = 11 × 9
5 × 5 = 99
25 = 3 24
25
( 7 8 + 2 9 ) × (36 × 1 79 )
63 + 16
( ) × 36
72 79 = 79
72 × 36
79 = 1 2
( 11
180 − 1 45 ) × (90 × 1 14 )
( 11 − 4
180 ) × (45 7 ) = 7
180 × 45
7 = 1 4
(2 − 1 3 − 1 5 ) × (6 − 1 11 )
( 30 − 5 − 3 ) × (5 11
15
11 − 1 11 )
22
15 × 5 10
11 = 22
15 × 65
11
2 × 13
= 26
3 3 = 8 2 3
( 9 3 − 1 4 − 1 8 − 1 16 ) × 8
(3 − 1 4 − 1 8 − 1 16 ) × 8
( 48 − 4 − 2 − 1 ) × 8
16
41
16 × 8 = 41
2 = 20 1 2
-25.
-26.
-27.
-28.
-29.
( 5 24 − 1 32 ) × (7 8 + 1 80 − 1 4 )
( 20 − 3
96
17
96 × 51
80
+ 1 − 30
) × (70 )
80
=
17 × 17
32 × 80 = 289
2 560
( 3 16 + 1 4 − 1 40 ) × (4 9 + 1 90 − 1 3 )
15 + 20 − 2 40 + 1 − 30
( ) × ( )
80
90
33
80 × 11
90
=
11 × 11
80 × 30 = 121
2 400
(2 1 3 + 3 1 4 ) × (3 + 4 1 4 + 1 16 )
(5 + 1 3 + 1 4 ) × (7 + 1 4 + 1 16 )
(5 + 4 + 3
12 ) × (7 + 4 + 1
16 )
5 7 12 × 7 5 16 = 67
12 × 117
16
2 613 53
= 40
64 64
=
67 × 39
4 × 16
150 × ( 9 32 + 5 + 1 16 ) × 1 14
150 × ( 9 + 160 + 2 ) × 1 32 14
150 × 171
32 × 1 75 × 171
=
14 16 × 14
12 825 57
= 57
224 224
-19.
(7 2 5 + 5 1 6 ) × (28 1 4 + 1 3 4 )
( 37
5 + 31
6 ) × (113 4 + 7 4 )
222 + 155
( ) × ( 120
30 4 )
377
× 30 = 377
30
(9 1 12 + 7 16 − 2 1 3 − 2) × 1 1 83
(5 1 12 + 7 16 − 1 3 ) × 84
83
( 61
12 + 7 16 − 1 3 ) × 84
83
244 + 21 − 16
( ) × 84
48 83 = 249
48 × 84
83
3 × 7
= 21
4 4 = 5 1 4
( 1 3 − 1 5 ) × ( 1 60 + 10
25 ) × 5 4 15
( 5 − 3 + 120
) × (5
15 300 ) × 79
15
2
15 × 125
300 × 79
15
=
25 × 79
3 × 150 × 15
79
3 × 6 × 15 = 79
270
LEONARDO F. APALA TITO 165