Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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SOLUCIONARIO DE ARITMETICA DE BALDOR-16. 11.94940691 1. 9 4 9 4 0 6 9 0-18. 9 663.494549 6 6 3. 4 9 4 5 4 0-17. 4 100.16177974 1 0 0. 1 6 1 7 7 9 7 0LEONARDO F. APALA TITO 262
SOLUCIONARIO DE ARITMETICA DE BALDOREJERCICIO 226Hallar la raíz cuadrada de:-1. 1 4-7. 63100√42√64 = 6 8 = 3 4 con error < 1 8-2. 1825-3. 3049-4. 5036-5. 6081√ 1 4 = √1√4 = 1 2√ 18 √2 ∙ 32=25 √25= 3 5 √2√18o también:√25 = 4 5 con error < 1 5√ 3049 = √30√49 = 1 7 √30√30O también:√49 = 5 7 con error < 1 7√ 5036 = √50√36√50=√2 ∙ 526O también:= 5 6 √2√36 = 7 6 = 1 1 6 con error < 1 6√ 6081 = √60√81 = √22 ∙ 159O también:= 2 9 √15-8. 80121-9. 96169O también:-10. 121144-11. 40289√ 63100 = √63√100 = √32 ∙ 710√63√ 80121 = √80O también:= 3 10 √7√100 = 7 10 con error < 1 10√121 = √24 ∙ 511√80√ 96169 = √96O también:= 2211 √5 = 4 11 √5√121 = 8 11 con error < 1 11√169 = √22 ∙ 2 2 ∙ 2 ∙ 313√96√ 40289 = √40√169 = 9 13 con error < 1 13√ 121144 = √121√144 = 1112√289 = √22 ∙ 2 ∙ 517O también:= 2 ∙ 2√6 = 4 13 13 √6= 2√2 ∙ 517= 2 17 √10-6. 4264√60√81 = 7 9 con error < 1 9√ 4264 = √42√64 = √428 = 1 8 √42O también:-12. 81225-13. 90256√40√289 = 6 17 con error < 1 17√ 81225 = √81√225 = 9 15 = 3 5LEONARDO F. APALA TITO 263
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Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

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