Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
5 177.4 m 2 + 143.8 m 2 = 5 321.2 m 2
-5. 3 cord. 2 50 v 2 a a
414.2
3 cord. 2 = 3 cord. 2 m2
×
1 cord. 2 × 1 a
100 m 2
= 12.426 a
50 v 2 = 50 v 2 0.719 m2
×
1 v 2 × 1 a
100 m 2
= 0.3595 a
Sumando:
12.426 a + 0.3595 a = 12 7855 a
-6. 3 cab 1 000 v 2 a a
134 202 m2
3 cab = 3 cab × × 1 a
1 cab 100 m 2
= 4 026.06 a
0.719
1 000 v 2 = 1 000 v 2 m2
×
1 v 2 × 1 a
100 m 2
= 7.19 a
Sumando:
4 026.06 a + 7.19 a = 4 033.25 a
-7. 5 cab 80 cord. 2 a ha
134 202 m2 1 ha
5 cab = 5 cab × ×
1 cab 10 000 m 2
= 67.101 ha
80 cord. 2 = 80 cord. 2 414.2 m2
×
1 cord. 2
1 ha
×
10 000 m 2
Sumando:
= 3.3136 ha
67.101 ha + 3.3136 ha = 70 4146 ha
-8. 3 garraf. 10 bot. a l
18.125 l
3 garraf. = 3 garraf.×
1 garraf.
= 54.375 l
0.725 l
10 bot. = 10 bot.× = 7.25 l
1 bot.
Sumando: 54.375 l + 7.25 l = 61.625 l
-9. 2 pipas 50 bot. a kl
435 l
2 pipas = 2 pipas ×
1 pipa × 1 kl
1 000 l
= 0.87 kl
0.725 l
50 bot = 50 bot.×
1 bot × 1 kl
1 000 l
= 0.03625 kl
Sumando: 0.87 kl + 0.03625 kl =
0.90625 kl
-10. 2@ 8 lb a kg
2@ = 2@ ×
25 lb 460 g
×
1@ 1 lb × 1 kg
1 000 g
= 23 kg
460 g
8 lb = 8 lb ×
1 lb × 1 kg
1 000 g
= 3.68 kg
Sumando: 23 kg + 3.68 kg = 26.68 kg
-11. 5 qq 10 lb a kg
5 qq = 5 qq × 4@
1 qq
25 lb 460 g
× ×
1@ 1 lb
× 1 kg = 230 kg
1 000 g
460 g
10 lb = 10 lb ×
1 lb × 1 kg
1 000 g
= 4.6 kg
Sumando: 230 kg + 4.6 kg = 234.6 kg
-12. 2 T a hg
20 qq
2 T = 2 T ×
1 T × 4@ 25 lb
×
1 qq 1@
460 g
×
1 lb × 1 hg
100 g
= 18 400 hg
EJERCICIO 270
Reducir:
-1. 8 000 v a cord, a leguas
1º: 8 000 v a cord.
8 000 v × 1 cord.
24 v = 333 1 3 cord.
2º: 8 000 v a leguas
8 000 v × 1 legua
5 000 v = 1 3 5 leguas
-2. 1 875 cord. a leguas
1 875 cord.× 1 legua
208 1 3 cord.
= 1 875
625/3 leguas
5 625
leguas = 9 leguas
625
-3. 2 000 v 2 a cord. plano
2 000 v 2 × 1 cord.2
576 v 2 = 3 17
36 cord.2
-4. 1 306 368 v 2 a cab
1 306 368 v 2 1 cab
×
186 624 v 2 = 7 cab
-5. 18 000 v 2 a mesanas
18 000 v 2 × 1 mes
3 600 v 2 = 5 mes
-6. 1 134 cord. 2 a cab
1 134 cord. 2 × 1 cab
324 cord. 2 = 3 1 2 cab
-7. 75 bot. a garraf.
75 bot × 1 garraf. = 3 garraf.
25 bot
-8. 2 400 bot. a garraf., a pipas
1º: 2 400 bot. a garraf.
2 400 bot × 1 garraf. = 96 garraf.
25 bot
2º: 2 400 bot. a pipas
2 400 bot = 96 garraf.× 1 pipa
24 garraf.
= 4 pipas
-9. 80 lb a arrobas
-10. 5 000 lb a T
80 lb × 1@
25 lb = 3 1 5 @
5 000 lb × 1@
25 lb × 1 qq
4@ × 1 T
20 qq = 2 1 2 T
EJERCICIO 271
Reducir:
-1. 50 m a v. a cord.
1º: 50 m a v
50 m × 1 v = 58.962 v
0.848 m
2º: 50 m a cord.
50 m × 1 cord. = 2.457 cord.
20.352 m
-2. 8 dam a cord.
10 m
8 dam ×
1 dam × 1 cord.
20.352 m
= 3.931 cord.
LEONARDO F. APALA TITO 350