Solucionario completo de Aritmetica de Baldor (Por Leonardo F. Apala T.)

SOLUCIONARIO DE ARITMETICA DE BALDOR
-10.
13 × 5 6 × 3 10 × 5 26 = 5
2 × 2 × 2 = 5 8
-18.
7 2 9 × 18 × 5 13 × 6 1 3 × 1 20
-6.
5
8 × 8 5 = 1
2 1 3 × 3 1 4 × 4 1 5 × 1
637
7
3 × 13
4 × 21
5 × 1
637 = 13 × 21
3 × 4 × 5 × 91
-11.
7
4 × 5 × 7 = 1 20
11
18 × 2 1 9 × 36 × 1 38
11
18 × 19
9 × 36 × 1 38 = 11 × 2
9 × 2 = 11
9 = 1 2 9
-12.
7 2 3 × 11
46 × 1
121 × 66
23
3 × 11
46 × 1
22
× 66 =
121 2 × 11 = 2 2 = 1
-13.
-14.
-15.
-16.
-17.
19 × 5 3 14 × 2 73 × 7 19
19 × 73
14 × 2 73 × 7 19 = 1
36 × 1 84 × 14
9 × 1 6 = 6
6 × 9 = 1 9
5 1 8 × 1 82 × 6 1 3 × 48
41
8 × 1 82 × 19 19 × 6
× 48 =
3 2 × 3 = 19
9 1 3 × 7 5 7 × 20 1 3 × 1
1 708
28
3 × 54
7 × 61
3 × 1
1 708 = 18
7 × 3 = 6 7
11
36 × 18
121 × 2 3 5 × 1
169 × 715
11
36 × 18
121 × 13
5 × 1
169 × 715
143
2 × 11 × 13 = 11
2 × 11 = 1 2
65
9 × 18 × 5 13 × 19
3 × 1 20 = 5 × 2 × 19
3 × 4
-19.
-20.
5 × 19
3 × 2 = 95
6 = 15 5 6
5 2 31 × 11
157 × 62
77 × 21 × 1 1 6
157
31 × 11
157 × 62
77 × 21 × 7 6
2 × 7 × 7
= 7
7 × 2
11
26 × 52 × 3 1 13 × 1 6 7 × 5 33
11 40
× 52 ×
26 13 × 13
7 × 5 33
2 × 40 × 5
= 400
7 × 3 21 = 19 1 21
EJERCICIO 136
MISCELANEA
Simplificar:
-1.
-2.
-3.
-4.
( 3 5 × 1 3 ) × 5 1 16 = 1 5 × 81
16 = 81
80 = 1 1 80
16 × (14 1 16 × 5 1 225
) = 16 ×
6 16 × 31
6
75 × 31
2
= 2 325 = 1 162 1 2
2
( 1 2 − 1 3 ) × 6 = (3 − 2
6 ) 6 = 1
( 1 2 + 3 4 ) × 1 5 = (2 + 3
4 ) × 1 5 = 5 4 × 1 5 = 1 4
-5.
(1 − 3 8 ) × 1 3 5 = (8 8 − 3 8 ) × 8 5
-7.
-8.
-9.
-10.
72 × ( 7 8 + 2 + 16
) = 72 × (63 )
9 72
63 + 16 = 79
(5 2 3 − 2 9 ) × 3 = (17 3 − 2 9 ) × 3
( 51 − 2 ) × 3 = 49
9
3 = 16 1 3
(4 + 2 3 5 ) × 1 66
(4 + 13
5 ) × 1 66 = 33
5 × 1 66 = 1 10
(8 − 2 9 ) × 1 35 = (7 9 9 − 2 9 ) × 1 35
7 7 9 × 1 35 = 70
9 × 1 35 = 2 9
(16 3 5 − 7 10 ) × 1
159 = (83 5 − 7 10 ) × 1
159
-11.
-12.
( 166 − 7 ) × 1
10 159 = 159
10 × 1
159 = 1 10
( 1 8 + 5 1 4 − 1 20 ) × 9 1 16
( 1 8 + 21
4 − 1 20 ) × 145
16
( 5 + 210 − 2 ) × 145
40 16 = 213
40 × 145
16
213 × 29
8 × 16 = 6 177
128
= 48
33
128
(1 3 4 − 1 8 − 1 16 ) × 2 3 = (7 4 − 1 8 − 1 16 ) × 2 3
-13.
( 28 − 2 − 1 ) × 2 16 3 = 25
16 × 2 3
25
8 × 3 = 25
24 = 1 1 24
LEONARDO F. APALA TITO 164