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Russel-Research-Method-in-Anthropology

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Bivariate Analysis: Test<strong>in</strong>g Relations 609<br />

This PRE measure of association for nom<strong>in</strong>al variables is called lambda,<br />

written either or L. Like all PRE measures of association, lambda has the<br />

nice quality of be<strong>in</strong>g <strong>in</strong>tuitively and directly <strong>in</strong>terpretable. A lambda of .33<br />

means that if you know the scores on an <strong>in</strong>dependent variable, you can guess<br />

the scores on the dependent variable 33% more of the time than if you didn’t<br />

know anyth<strong>in</strong>g about the <strong>in</strong>dependent variable.<br />

Chi-Square<br />

While lambda demonstrates the <strong>in</strong>tuitively compell<strong>in</strong>g PRE pr<strong>in</strong>ciple, there<br />

are problems with it. There is no way to test whether any value of lambda<br />

shows a particularly strong or weak relationship between variables; it can take<br />

different values depend<strong>in</strong>g on whether you set up the dependent variable <strong>in</strong><br />

the rows or the columns; and it can be very low, even when there is an <strong>in</strong>tuitively<br />

clear association between nom<strong>in</strong>al variables. Lambda for table 20.4a,<br />

for example, is just .10—that is, if you guess that all white families with children<br />

<strong>in</strong> the United States have two parents and that all black families have one<br />

parent, you make 10% fewer errors than if you guess that all families have two<br />

parents.<br />

With bivariate data on nom<strong>in</strong>al variables, many researchers use 2 (chisquare).<br />

Chi-square tells you whether or not a relation exists between or<br />

among variables and it tells you the probability that a relation is the result of<br />

chance. But it is not a PRE measure of correlation, so it doesn’t tell you the<br />

strength of association among variables.<br />

The pr<strong>in</strong>cipal use of 2 , then, is for test<strong>in</strong>g the null hypothesis that there is<br />

no relation between two nom<strong>in</strong>al variables. If, after a really good faith effort,<br />

we fail to accept the null hypothesis, we can reject it. Us<strong>in</strong>g this approach, we<br />

never prove anyth<strong>in</strong>g us<strong>in</strong>g statistical tests like 2 . We just fail to disprove<br />

th<strong>in</strong>gs. As it turns out, that’s quite a lot.<br />

Calculat<strong>in</strong>g 2<br />

The formula for calculat<strong>in</strong>g 2 for a bivariate table is the same as the one<br />

we saw <strong>in</strong> chapter 19 for a univariate distribution. Here it is aga<strong>in</strong>:<br />

2 (OE)2<br />

Formula 20.6<br />

E<br />

where O represents the observed number of cases <strong>in</strong> a particular cell of a<br />

bivariate table, and E represents the number of cases you’d expect for that cell<br />

if there were no relation between the variables <strong>in</strong> that cell.

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