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Statistics for the Behavioral Sciences by Frederick J. Gravetter, Larry B. Wallnau ISBN 10: 1305504917 ISBN 13: 9781305504912

Statistics is one of the most practical and essential courses that you will take, and a primary goal of this popular text is to make the task of learning statistics as simple as possible. Straightforward instruction, built-in learning aids, and real-world examples have made STATISTICS FOR THE BEHAVIORAL SCIENCES, 10th Edition the text selected most often by instructors for their students in the behavioral and social sciences. The authors provide a conceptual context that makes it easier to learn formulas and procedures, explaining why procedures were developed and when they should be used. This text will also instill the basic principles of objectivity and logic that are essential for science and valuable in everyday life, making it a useful reference long after you complete the course.

Statistics is one of the most practical and essential courses that you will take, and a primary goal of this popular text is to make the task of learning statistics as simple as possible. Straightforward instruction, built-in learning aids, and real-world examples have made STATISTICS FOR THE BEHAVIORAL SCIENCES, 10th Edition the text selected most often by instructors for their students in the behavioral and social sciences. The authors provide a conceptual context that makes it easier to learn formulas and procedures, explaining why procedures were developed and when they should be used. This text will also instill the basic principles of objectivity and logic that are essential for science and valuable in everyday life, making it a useful reference long after you complete the course.

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SECTION 6.3 | Probabilities and Proportions for Scores from a Normal Distribution 177

The final step is to transform the z-score into an X value. By definition, a z-score

of +1.28 corresponds to a score that is located above the mean by 1.28 standard deviations.

One standard deviation is equal to 10 points (σ = 10), so 1.28 standard deviations is

1.28 σ = 1.28(10) = 12.8 points

Thus, our score is located above the mean (μ = 24.3) by a distance of 12.8 points.

Therefore,

X = 24.3 + 12.8 = 37.1

The answer for our original question is that you must commute at least 37.1 minutes a

day to be in the top 10% of American commuters.

EXAMPLE 6.11

Again, the distribution of commuting times for American workers is normal with a mean

of μ = 24.3 minutes and a standard deviation of σ = 10 minutes. For this example, we will

find the range of values that defines the middle 90% of the distribution. The entire distribution

is shown in Figure 6.15 with the middle portion shaded.

The 90% (0.9000) in the middle of the distribution can be split in half with 45% (0.4500)

on each side of the mean. Looking up 0.4500, in column D of the unit normal table, you

will find that the exact proportion is not listed. However, you will find 0.4495 and 0.4505,

which are equally close. Technically, either value is acceptable, but we will use 0.4505 so

that the total area in the middle is at least 90%. Reading across the row, you should find a

z-score of z = 1.65 in column A. Thus, the z-score at the right boundary is z = +1.65 and

the z-score at the left boundary is z = –1.65. In either case, a z-score of 1.65 indicates a

location that is 1.65 standard deviations away from the mean. For the distribution of commuting

times, one standard deviation is σ = 10, so 1.65 standard deviations is a distance of

1.65 σ = 1.65(10) = 16.5 points

Therefore, the score at the right-hand boundary is located above the mean by 16.5 points

and corresponds to X = 24.3 + 16.5 = 40.8. Similarly, the score at the left-hand boundary

is below the mean by 16.5 points and corresponds to X = 24.3 – 16.5 = 7.8. The

middle 90% of the distribution corresponds to values between 7.8 and 40.8. Thus, 90% of

American commuters spend between 7.8 and 40.8 minutes commuting to work each day.

Only 10% of commuters spend either more time or less time.

Middle 90%

s 5 10

FIGURE 6.15

The distribution of commuting

times for American

workers. The problem is to

find the middle 90% of the

distribution.

7.8 m 5 24.3 40.8

21.65 0

1.65

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