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Statistics for the Behavioral Sciences by Frederick J. Gravetter, Larry B. Wallnau ISBN 10: 1305504917 ISBN 13: 9781305504912

Statistics is one of the most practical and essential courses that you will take, and a primary goal of this popular text is to make the task of learning statistics as simple as possible. Straightforward instruction, built-in learning aids, and real-world examples have made STATISTICS FOR THE BEHAVIORAL SCIENCES, 10th Edition the text selected most often by instructors for their students in the behavioral and social sciences. The authors provide a conceptual context that makes it easier to learn formulas and procedures, explaining why procedures were developed and when they should be used. This text will also instill the basic principles of objectivity and logic that are essential for science and valuable in everyday life, making it a useful reference long after you complete the course.

Statistics is one of the most practical and essential courses that you will take, and a primary goal of this popular text is to make the task of learning statistics as simple as possible. Straightforward instruction, built-in learning aids, and real-world examples have made STATISTICS FOR THE BEHAVIORAL SCIENCES, 10th Edition the text selected most often by instructors for their students in the behavioral and social sciences. The authors provide a conceptual context that makes it easier to learn formulas and procedures, explaining why procedures were developed and when they should be used. This text will also instill the basic principles of objectivity and logic that are essential for science and valuable in everyday life, making it a useful reference long after you complete the course.

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514 CHAPTER 15 | Correlation

The process of finding ranks for tied scores is demonstrated here. These scores have

been listed in order from smallest to largest.

Scores Rank Position Final Rank

3 1 1.5

3 2 1.5

5 3 3

6 4 5

6 5 5

6 6 5

12 7 7

Mean of 1 and 2

Mean of 4, 5, and 6

Note that this example has seven scores and uses all seven ranks. For X = 12, the

largest score, the appropriate rank is 7. It cannot be given a rank of 6 because that rank

has been used for the tied scores.

Caution: In this formula,

you compute the value

of the fraction and then

subtract from 1. The 1 is

not part of the fraction.

EXAMPLE 15.12

■ Special Formula for the Spearman Correlation

After the original X values and Y values have been ranked, the calculations necessary for

SS and SP can be greatly simplified. First, you should note that the X ranks and the Y ranks

are really just a set of integers: 1, 2, 3, 4, . . . , n. To compute the mean for these integers,

you can locate the midpoint of the series by M = (n + 1)/2. Similarly, the SS for this series

of integers can be computed by

SS 5 nsn2 2 1d

sTry it out.d

12

Also, because the X ranks and the Y ranks are the same values, the SS for X is identical to

the SS for Y.

Because calculations with ranks can be simplified and because the Spearman correlation

uses ranked data, these simplifications can be incorporated into the final calculations

for the Spearman correlation. Instead of using the Pearson formula after ranking the data,

you can put the ranks directly into a simplified formula:

r S

5 1 2

6oD2

nsn 2 2 1d

(15.9)

where D is the difference between the X rank and the Y rank for each individual. This

special formula produces the same result that would be obtained from the Pearson formula.

However, note that this special formula can be used only after the scores have been

converted to ranks and only when there are no ties among the ranks. If there are relatively

few tied ranks, the formula still may be used, but it loses accuracy as the number of ties

increases. The application of this formula is demonstrated in the following example.

To demonstrate the special formula for the Spearman correlation, we use the same data that

were presented in Example 15.11. The ranks for these data are shown again here:

Ranks Difference

X Y D D 2

1 5 4 16

2 3 1 1

3 4 1 1

4 2 –2 4

5 1 –4 16

38 = ∑D 2

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