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Corrigé des exercices - Dunod

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392<br />

Comme la série de terme général k(1 −p) k−1 converge absolument, Y admet une espérance.<br />

E(Y ) =<br />

+∞∑<br />

k=M<br />

kP(Z = k)<br />

= M − M(1 − p) M +<br />

+∞∑<br />

k=M+1<br />

kp(1 − p) k−1<br />

= M − M(1 − p) M + (M + 1)(1 − p)M − M(1 − p) M+1<br />

p<br />

(1 − p)M<br />

= M +<br />

p<br />

Exercice 31.10<br />

1. X 1 , X 2 , X 3 sont <strong>des</strong> variables aléatoires réelles indépendantes qui suivent une loi uniforme<br />

sur [1,n].<br />

En utilisant le système complet d’événements (X 3 = k) k∈[1,n] ,<br />

P(X 3 = X 1 + X 2 ) =<br />

n∑<br />

P(X 1 + X 2 = k,X 3 = k) =<br />

k=1<br />

n∑<br />

P(X 1 + X 2 = k)P(X 3 = k)<br />

k=1<br />

En utilisant le système complet d’événements (X 2 = i) i∈[1,n] ,<br />

2. (X,Y,Z)(Ω) =<br />

P(X 3 = X 1 + X 2 ) =<br />

Soit (i,j,k) ∈ (X,Y,Z)(Ω).<br />

Si i = j = k, alors<br />

=<br />

=<br />

n∑<br />

n∑<br />

P(X 3 = k) P(X 1 + X 2 = k,X 2 = i)<br />

k=1<br />

k=1<br />

i=1<br />

n∑<br />

n∑<br />

P(X 3 = k) P(X 1 = k − i)P(X 2 = i)<br />

k=2<br />

i=1<br />

n−1<br />

∑<br />

k−1<br />

∑<br />

P(X 3 = k) P(X 1 = k − i)P(X 2 = i)<br />

= 1 ∑ n<br />

n 3 k − 1<br />

k=1<br />

= n − 1<br />

2n 2<br />

{<br />

}<br />

(i,j,k) ∈ [1,n] 3 , i j k .<br />

i=1<br />

P((X,Y,Z) = (i,j,k)) = P(X 1 = i,X 2 = i,X 3 = i) = 1 n 3 .

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