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998<br />

12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Eleven Answers and Explanations<br />

11<br />

9. 2.75 or 4<br />

Difficulty: Medium<br />

Strategic Advice: Many <strong>SAT</strong> questions require multiple<br />

steps. In this case, first find <strong>the</strong> value of d from <strong>the</strong> second<br />

equation, <strong>the</strong>n use that in <strong>the</strong> first equation to find <strong>the</strong> value<br />

of h.<br />

Getting to <strong>the</strong> Answer:<br />

4d = 10<br />

d =J.Q=2<br />

4 2<br />

d+ 2h = 8<br />

+2h =<br />

2 8<br />

2h =<br />

2 2 2<br />

h =<br />

4<br />

10. 6<br />

Difficulty: Low<br />

_ 2_ = _!_<br />

_!_<br />

Strategic Advice: First, subtract <strong>the</strong> fixed cost from <strong>the</strong> total<br />

amount Mr. Jones was charged to find <strong>the</strong> amount he spent<br />

on books. Then, divide this by <strong>the</strong> cost of one book to find<br />

<strong>the</strong> number of books he ordered.<br />

Getting to <strong>the</strong> Answer:<br />

62 -35 =27<br />

27<br />

=<br />

4.50 6<br />

11. 12<br />

Difficulty: Medium<br />

Strategic Advice: Sketching a diagram will often help you<br />

visualize geometry problems. Think about <strong>the</strong> relationship<br />

between <strong>the</strong> lengths of <strong>the</strong> different line segments in this<br />

problem.<br />

Getting to <strong>the</strong> Answer:<br />

Since C is <strong>the</strong> midpoint of segment AO, which is 16 cm<br />

long, segments AC and CO must each be 8 cm long. B<br />

is <strong>the</strong> midpoint of AC, so AB and BC are each 4 cm long.<br />

Segment BO is 4 + 8 = 1 2 cm long.<br />

12. 3<br />

Difficulty: Medium<br />

Strategic Advice: This particular problem can easily be<br />

solved by Picking Numbers. Since <strong>the</strong> digits of number M<br />

are <strong>the</strong> same, <strong>the</strong>re are only 9 possible numbers to try.<br />

On top of that, you can quickly see that <strong>for</strong> any A > 3 , <strong>the</strong><br />

product will be a four-digit number, ruling out 3-9. Try<br />

starting with 2 or 1.<br />

Getting to <strong>the</strong> Answer:<br />

11<br />

--2Ll.l.<br />

121<br />

1 + 2 = 3<br />

13. 1,000<br />

Difficulty: Medium<br />

Strategic Advice: This question deals with finding <strong>the</strong><br />

number of possible combinations of two objects. No matter<br />

which entree Mary selects, she could order any of <strong>the</strong> 40<br />

side dishes.<br />

Getting to <strong>the</strong> Answer:<br />

25 x 40 = 1,000<br />

14. 25<br />

Difficulty: Medium<br />

Strategic Advice: One approach to this problem would<br />

be to draw a calendar, placing <strong>the</strong> first of <strong>the</strong> month on<br />

Monday and counting <strong>the</strong> days between that and <strong>the</strong> last<br />

Friday. While this technique doesn't take too long on this<br />

particular problem, it can be cumbersome when dealing<br />

with larger numbers. A faster approach is shown below.<br />

Getting to <strong>the</strong> Answer:<br />

The last Friday in <strong>the</strong> month is four days after <strong>the</strong> last<br />

Monday. The last Monday in <strong>the</strong> month is some multiple<br />

of seven days after <strong>the</strong> first Monday. There<strong>for</strong>e, <strong>the</strong> last<br />

Friday is 7n + 4 days after <strong>the</strong> first Monday, where n is an<br />

integer. The largest possible value of 7n + 4 that is less<br />

than 31 is 25.<br />

15. 812<br />

Difficulty: Medium<br />

Strategic Advice: Although you could find <strong>the</strong> value<br />

of 29! and <strong>the</strong> value of 27!, this would be extremely

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