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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong> /<br />

Practice Test Eight Answers and Explanations 735<br />

7. B<br />

Difficulty: Medium<br />

Strategic Advice: Don't let <strong>the</strong> difference between inches<br />

and feet confuse you here. Stay focused on using feet <strong>for</strong><br />

your answer.<br />

Getting to <strong>the</strong> Answer:<br />

For each hair bow, 3 pieces of 8-inch-long ribbon are used,<br />

so that is 24 inches or 2 feet of ribbon. She made g hair<br />

bows, so <strong>the</strong> total amount of ribbon she used was 2g.<br />

So if <strong>the</strong> spool has 200 feet of ribbon, we can say that<br />

she used 200 - 2g feet of ribbon.<br />

8. B<br />

Difficulty: High<br />

Strategic Advice: If a geometry question does not provide a<br />

diagram, sketch your own. Important things to notice about<br />

this problem are <strong>the</strong> radius of <strong>the</strong> circle and <strong>the</strong> base and<br />

height of <strong>the</strong> triangle.<br />

Getting to <strong>the</strong> Answer:<br />

To find <strong>the</strong> probability that a randomly selected point from<br />

within <strong>the</strong> circle will fall within <strong>the</strong> triangle, find <strong>the</strong> area of<br />

<strong>the</strong> triangle and divide it by <strong>the</strong> area of <strong>the</strong> circle.<br />

Radius: 3<br />

Base: 6<br />

Height: 3<br />

Area of triangle: -jC6)(3) = 9<br />

Area of circle: n(32) = 97t<br />

Probability: ..2_ = .l<br />

7t<br />

9. 1 2 or .5<br />

97t<br />

Difficulty: Medium<br />

Strategic Advice: You're given that <strong>the</strong> whole line segment,<br />

AE, is 3. Since D is <strong>the</strong> midpoint of AE, D must cutAf in<br />

half. That means that AD is 1 -j and Of is 1 -j.<br />

10. 70<br />

Difficulty: Medium<br />

Strategic Advice: If you notice that <strong>the</strong>re is a triangle<br />

on <strong>the</strong> right side of <strong>the</strong> figure with two labeled angles<br />

from that triangle, you can probably solve this one.<br />

Getting to <strong>the</strong> Answer:<br />

The two labeled angles are 60° and 80°, so <strong>the</strong> third angle<br />

of <strong>the</strong> triangle must be 1 80 - 60 - 80 = 40°. The 40°<br />

angle and <strong>the</strong> two angles labeled cf' make up a straight line,<br />

so 40 + d + d = 1 80. That means that 40 + 2d = 1 80,<br />

2d = 140, and d = 70, so grid in <strong>the</strong> number 70.<br />

17 11. 9, 1.88, or 1.89<br />

Difficulty: Medium<br />

Strategic Advice: Here you could do a lot of arithmetic<br />

and get <strong>the</strong> right answer, but you should have noticed a<br />

shortcut. Since this is a long string of numbers that are<br />

being added and subtracted, you don't really need <strong>the</strong><br />

paren<strong>the</strong>ses. Note: If <strong>the</strong>re was a subtraction sign in front of<br />

<strong>the</strong> paren<strong>the</strong>ses, it would need to be distributed.<br />

Getting to <strong>the</strong> Answer:<br />

You can add or subtract <strong>the</strong>se fractions in any order. Notice<br />

that at one point you are adding t and at ano<strong>the</strong>r point<br />

subtracting t· Plus t minus t is just 0. The same is true<br />

of 1<br />

- and .l, so you can just cross out <strong>the</strong> terms - .l,<br />

5 7 3<br />

+ 1 - 1 1 1 d 1 h I<br />

3, S ' + S' - 7 , an + 7' T at eaves you wit<br />

x = 2 - .l = _.!._§_ - .l = .lZ. so grid in .lZ. (Not 1 <br />

9 9 9 9' 9 · 9 ·<br />

You can't grid in mixed numbers.)<br />

· h<br />

Getting to <strong>the</strong> Answer:<br />

AD is made up of three small line segments, all of which are<br />

equal in length. That means that each one must measure<br />

one-third of 1 -j. which is -j. So AB has length -j. and you<br />

can put -j or .5 into your grid.

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