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12.Practice.Tests.for.the.SAT_2015-2016_1128p

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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Two Answers an d Exp l anations<br />

l13<br />

I<br />

180-130=X<br />

50=x<br />

16. 115<br />

Difficu l ty: High<br />

Strategic A d vice: The tangent line here <strong>for</strong>ms <strong>the</strong> third side<br />

of a triangle. Since <strong>the</strong> shaded portion is exactly t <strong>the</strong> area<br />

of circle A, LBAD = go0• Use this in<strong>for</strong>mation to find LBDA.<br />

Find LCDE by using <strong>the</strong> fact that LCDE and LBDA are<br />

supplementary.<br />

Getting to t h e Answer:<br />

LBDA = 180° - 25° - go0 = 65°<br />

LCDE = 180°-65°= 115°<br />

17. 10<br />

Difficu l ty: High<br />

Strategic A d vice: The shaded region is just <strong>the</strong> area of <strong>the</strong><br />

larger triangle minus <strong>the</strong> area of <strong>the</strong> smaller triangle. Set<br />

up an equation using this in<strong>for</strong>mation. Be<strong>for</strong>e you grid in<br />

your answer, make sure you're answering <strong>the</strong> right question<br />

(height of smaller triangle).<br />

Getting to t h e Answer:<br />

Large triangle: base = 15; height =x + 6<br />

Small triangle: base = g; height =x<br />

Shaded area = large area - small area =<br />

CCD

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