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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

834 Practice Test Nine Answers and Explanations<br />

If <strong>the</strong>re are 2 ounces of alcohol left after starting with 16<br />

ounces, <strong>the</strong>n 1 6 - 2 = 1 4 ounces must have evaporated,<br />

so <strong>the</strong> correct answer is 14, (E).<br />

10. B<br />

Difficulty: High<br />

Strategic Advice: The shaded region is one of four equal<br />

pieces left when <strong>the</strong> circle is subtracted from <strong>the</strong> square.<br />

So to find <strong>the</strong> area of <strong>the</strong> shaded region, you must subtract<br />

<strong>the</strong> area of <strong>the</strong> circle from <strong>the</strong> area of <strong>the</strong> square and <strong>the</strong>n<br />

take f of this difference. You must first find <strong>the</strong> area of <strong>the</strong><br />

circle and <strong>the</strong> area of <strong>the</strong> square. To find <strong>the</strong> area of <strong>the</strong><br />

circle, you must know its radius.<br />

Getting to <strong>the</strong> Answer:<br />

You're told that <strong>the</strong> circumference of <strong>the</strong> circle is 47t. You<br />

also know that <strong>the</strong> circumference C of a circle is related to<br />

its radius r by <strong>the</strong> <strong>for</strong>mula C = 2w. So here, 47t = 2w and<br />

r = 2. The area of <strong>the</strong> circle is w2, which equals 7t(2)2 or 47t.<br />

To find <strong>the</strong> area of <strong>the</strong> square, you must know <strong>the</strong> length<br />

of its side. If you draw in <strong>the</strong> diameter of <strong>the</strong> circle whose<br />

endpoints are <strong>the</strong> point where <strong>the</strong> circle touches side BC<br />

of <strong>the</strong> square and <strong>the</strong> point where <strong>the</strong> circle touches side<br />

AD of <strong>the</strong> square, you'll see that <strong>the</strong> side of <strong>the</strong> square is<br />

equal in length to <strong>the</strong> diameter of <strong>the</strong> circle. The radius of<br />

<strong>the</strong> circle is 2, so its diameter, which is twice <strong>the</strong> radius, is<br />

2 x 2 or 4. Since <strong>the</strong> side of <strong>the</strong> square is 4, its area is its<br />

side squared or 42, which is 16. The area of <strong>the</strong> square is<br />

16 and <strong>the</strong> area of <strong>the</strong> circle is 47t, so <strong>the</strong> area outside <strong>the</strong><br />

circle and inside <strong>the</strong> square is 1 6 - 47t. So <strong>the</strong> area of <strong>the</strong><br />

shaded region is 1 6 47t = 4 _ 7t.<br />

11. B<br />

Difficulty: Medium<br />

Strategic Advice: Drawing a diagram is <strong>the</strong> key to solving<br />

this problem.<br />

Getting to <strong>the</strong> Answer:<br />

Draw two parallel lines, m and n; now draw three different<br />

transversals through <strong>the</strong>m, trying to <strong>for</strong>m <strong>the</strong> least number<br />

of points of intersection.<br />

From <strong>the</strong> diagram above, you can see that <strong>the</strong> number is<br />

4, since <strong>the</strong> three transversals can pass through <strong>the</strong> first<br />

parallel line at different points, yet pass through a common<br />

point on <strong>the</strong> second parallel line.<br />

12. D<br />

Difficulty: Medium<br />

Strategic Advice: Think about <strong>the</strong> graph of each answer<br />

choice. If several look similar, or if you're not sure what an<br />

equation should look like when graphed, try plugging in<br />

<strong>the</strong> in<strong>for</strong>mation given in <strong>the</strong> figure above.<br />

Getting to <strong>the</strong> Answer:<br />

For instance, you could use <strong>the</strong> in<strong>for</strong>mation <strong>for</strong> <strong>the</strong> year<br />

1 992. This is 1 992-1 980 = 12 years after <strong>the</strong> study began,<br />

so t = 12. From <strong>the</strong> graph, d = 800. Plug <strong>the</strong>se numbers<br />

into each equation to see which one is true: (100)2 .lf =<br />

(100)23 = (100)8 = 800, so (D) is correct.<br />

13. E<br />

Difficulty: Medium<br />

Strategic Advice: Remember, <strong>the</strong> value of r(x) is shown by<br />

<strong>the</strong> y-value of each point.<br />

Getting to <strong>the</strong> Answer:<br />

When r(x) = 0, <strong>the</strong> graph touches <strong>the</strong> x-axis. This graph<br />

touches <strong>the</strong> x-axis at x = -5 and x = - 1 .<br />

m<br />

n

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