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12.Practice.Tests.for.the.SAT_2015-2016_1128p

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l 2 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Seven Answers and Explanations 653<br />

I<br />

Getting to <strong>the</strong> Answer:<br />

8. A<br />

f(2) = 2 + 4 = =3<br />

2 2<br />

g(2) = 22 - 6=4-6 =-2<br />

3-(-2) =3+2=5<br />

Difficulty: High<br />

Strategic Advice: This question involves <strong>the</strong> range-that is,<br />

all possible values-of d(w). Think about <strong>the</strong> limits of <strong>the</strong><br />

function. Is <strong>the</strong>re a number it must be smaller than? Is <strong>the</strong>re<br />

a number it must be larger than?<br />

Getting to <strong>the</strong> Answer:<br />

w2 0, since any real number squared must be positive.<br />

w2 + 11<br />

VW2+11<br />

The only answer choice that is not greater than or equal<br />

to 1 is (A).<br />

9. 5.50<br />

Difficulty: Low<br />

Strategic Advice: Be careful not to lose points on simple<br />

arithmetic questions.<br />

Getting to <strong>the</strong> Answer:<br />

Buying 12 tickets separately costs 12 times $1.50, or<br />

$1 8. Buying a dozen tickets at once costs $ 1 2.50, so <strong>the</strong><br />

difference in cost is $ 1 8 - $12.50, which equals $5.50.<br />

10. 49<br />

Difficulty: Low<br />

Strategic Advice: Notice that a side of square C is made up<br />

of a side of square A and a side of square B. The area of a<br />

square is <strong>the</strong> square of <strong>the</strong> length of a side.<br />

Getting to <strong>the</strong> Answer:<br />

Since <strong>the</strong> area of square A is 9, its side is 3; since <strong>the</strong> area<br />

of square B is 16, its side is 4. This makes a side of square C<br />

equal to 3 + 4 = 7, so its area is 49.<br />

11. 3 5 6<br />

Difficulty: Medium<br />

Strategic Advice: In this problem, you need to work with a<br />

system of equations.<br />

Getting to <strong>the</strong> Answer:<br />

You're asked <strong>for</strong> <strong>the</strong> value of rs, so solve <strong>for</strong> t in terms of s in<br />

<strong>the</strong> first equation and plug that into <strong>the</strong> second equation.<br />

-4=5<br />

t<br />

s=9t<br />

2- =t<br />

9<br />

Plug% <strong>for</strong> t in <strong>the</strong> second equation:<br />

5rt + 2 = 6<br />

5r(%) + 2 = 6<br />

12. 6 or 8<br />

2 rs =4<br />

9<br />

rs = 4 x .2.<br />

5<br />

rs = 36<br />

5<br />

Difficulty: Medium<br />

Strategic Advice: This can be solved by trial and error. Try<br />

different values of n until you find one that fits <strong>the</strong> given<br />

conditions.<br />

Getting to <strong>the</strong> Answer:<br />

You want 3n + 5 to be between 20 and 40. If n = 6, <strong>the</strong>n<br />

3n + 5 = 3(6) + 5 = 23, which is a prime number between<br />

20 and 40. So 6 is a correct answer. Ano<strong>the</strong>r correct answer<br />

is 8, since 3(8) + 5 = 29, which is also a prime number<br />

between 20 and 40.<br />

13. 21 or 28<br />

Difficulty: Medium<br />

Strategic Advice: This problem requires an understanding<br />

of how ratios work.<br />

Getting to <strong>the</strong> Answer:<br />

Since <strong>the</strong> ratio of boys to girls in <strong>the</strong> class is 3 to 4, <strong>the</strong> total<br />

number of students in <strong>the</strong> class must be a multiple of 3 +<br />

4, or 7. The multiples of 7 between 20 and 30 are 21 and<br />

28. Ei<strong>the</strong>r answer is correct.<br />

14. 80<br />

Difficulty: Medium<br />

Strategic Advice: Find how many CDs she can fit in length,<br />

<strong>the</strong>n in width, <strong>the</strong>n in height.

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