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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

728<br />

Practice Test Eight Answers and Explanations<br />

Getting to <strong>the</strong> Answer:<br />

This question is really just a rearrangement of <strong>the</strong> average<br />

<strong>for</strong>mula. Since we are dealing with prices in this question,<br />

<strong>the</strong> average <strong>for</strong>mula is this:<br />

sum of <strong>the</strong> pr _<br />

ices = average of <strong>the</strong> prices<br />

number of prices<br />

If we multiply both sides of <strong>the</strong> <strong>for</strong>mula by <strong>the</strong> number<br />

of prices, we get that <strong>the</strong> sum of <strong>the</strong> prices = average of<br />

<strong>the</strong> prices x number of prices, <strong>the</strong> quantity quoted in <strong>the</strong><br />

question. Thus, (D) is <strong>the</strong> correct choice.<br />

16. E<br />

Difficulty: Medium<br />

Strategic Advice: Equilateral means equal in length. So<br />

an equilateral triangle is a triangle whose three sides are<br />

all equal in length. So if <strong>the</strong> expressions 3x + 1 and x +<br />

7 represent sides of an equilateral triangle, <strong>the</strong>y must be<br />

equal.<br />

Getting to <strong>the</strong> Answer:<br />

Use this to set up an algebraic equation, 3x + 1 =x + 7,<br />

which can be solved <strong>for</strong> x. The result is x = 3, and all you<br />

have to do is plug that into ei<strong>the</strong>r expression. That will tell<br />

you that <strong>the</strong> length of a side of this equilateral triangle is<br />

10, so <strong>the</strong> perimeter, which is <strong>the</strong> sum of <strong>the</strong> length of <strong>the</strong><br />

sides, is equal to 10 + 1 0 + 10, or 30, (E).<br />

17. c<br />

Difficulty: Medium<br />

Strategic Advice: Since we have a word problem with<br />

numbers in <strong>the</strong> answer choices, Backsolving might be a<br />

good strategy to try here.<br />

Getting to <strong>the</strong> Answer:<br />

Since we are dealing with crayons, we know that <strong>the</strong><br />

number of crayons of each color will have to be an integer.<br />

Using choice (C), 20 x i = 8, which is a whole number,<br />

and 20 x ± = 5, also a whole number, so 20 is a possible<br />

value <strong>for</strong> <strong>the</strong> number of crayons, and (C) is <strong>the</strong> correct<br />

choice.<br />

18. A<br />

Difficulty: High<br />

Strategic Advice: Picking Numbers is always a good choice<br />

<strong>for</strong> a question with multiple variables in <strong>the</strong> question stem<br />

and answer choices.<br />

Getting to <strong>the</strong> Answer:<br />

Let's have x = 8 and y = 7. We know that <strong>the</strong> initial<br />

amount + 6 liters - 7 liters must equal 8 liters. In o<strong>the</strong>r<br />

words, <strong>the</strong> initial amount decreased by 1 liter becomes<br />

8 liters, so <strong>the</strong> initial amount of water must have been<br />

9 liters. Now we just have to substitute x and y into <strong>the</strong><br />

answer choices to see which one gives us 9 liters.<br />

8 + 7 - 6 = 9, so (A) is <strong>the</strong> correct choice.<br />

19. D<br />

Difficulty: High<br />

Strategic Advice: Anytime you are given a diagram that does<br />

not show all <strong>the</strong> in<strong>for</strong>mation given in <strong>the</strong> question, it is a good<br />

idea to draw that in<strong>for</strong>mation into <strong>the</strong> diagram.<br />

Getting to <strong>the</strong> Answer:<br />

/I<br />

/I<br />

y<br />

I I<br />

I I<br />

I I<br />

,J_ I<br />

12 1<br />

I<br />

In <strong>the</strong> diagram above, we have drawn in <strong>the</strong> height of <strong>the</strong><br />

pyramid and labeled <strong>the</strong> known lengths. We can find YZ<br />

by recognizing that it is <strong>the</strong> hypotenuse of <strong>the</strong> right triangle<br />

XYZ as labeled in <strong>the</strong> diagram above. If we can find <strong>the</strong><br />

lengths of <strong>the</strong> o<strong>the</strong>r two sides, we can use <strong>the</strong> Pythagorean<br />

<strong>the</strong>orem to find YZ. We already know that XY = 12, and<br />

XZ is equal to half of <strong>the</strong> diagonal of <strong>the</strong> square base.<br />

To find <strong>the</strong> length of this diagonal, we know that it is <strong>the</strong><br />

hypotenuse of ano<strong>the</strong>r right triangle whose legs are sides<br />

of <strong>the</strong> base. There<strong>for</strong>e, since <strong>the</strong> length of both legs is 1 6,<br />

we know this is a 45-45-90 triangle, making <strong>the</strong> length<br />

of <strong>the</strong> diagonal 1 6\/2. There<strong>for</strong>e, XZ = 8\/2. Using <strong>the</strong><br />

Pythagorean <strong>the</strong>orem,<br />

(YZ)2 = 122 + (8\/2)2<br />

(\'2')2 = 144 + 128<br />

yz=\/272<br />

yz= 4'\/'17<br />

z

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