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12.Practice.Tests.for.the.SAT_2015-2016_1128p

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12 Practice <strong>Tests</strong> <strong>for</strong> t h e <strong>SAT</strong> I<br />

Practice Test Four Answers and Explanations<br />

383<br />

T h is is t h e sma ll est num b er. T h e median wi ll b e x + 2,<br />

or 100.<br />

13. 4<br />

Difficulty: Medium<br />

Strategic Advice: Use t h e grap h to find t h e va l ue of h (x),<br />

t h en use t h ey-coordinate in your k function.<br />

Getting to <strong>the</strong> Answer:<br />

k (-2) = h ( - }) + 3 = h (-1) + 3 = 1 + 3 = 4<br />

( h (-1) = 1 came from t h e point (-1, 1) on t h e grap h )<br />

14. 120<br />

Difficulty: Hig h<br />

Strategic Advice: How many c oices does first friend h ave?<br />

T h en h ow many ponies does t h at l eave <strong>for</strong> t h e second friend?<br />

Getting to <strong>the</strong> Answer:<br />

T h e first friend h as h is or h er c h oice of 5 ponies, w h ic h<br />

l eaves 4 <strong>for</strong> t h e secon d friend, 3 <strong>for</strong> t h e t h ird friend, 2 <strong>for</strong><br />

t h e fourt h friend, and t h e l ast one is stuck wit h t h e l ast pony.<br />

So t h e num b er of possi b i l ities is<br />

5 x 4 x 3 x 2 x 1 = 120<br />

15. 50<br />

Difficulty: Medium<br />

Strategic Advice: Try to find t h e ot h er ang l es of ti.ABC.<br />

Getting to <strong>the</strong> Answer:<br />

Since MBC is isosce l es, ang l e B is a l so 50°, and ang l e ACB<br />

is 180° - 50° - 50° = 80°.<br />

ACD is a l ine, so<br />

80° + x + x = 1 80°<br />

80° + 2x = 1 80°<br />

2x= 100°<br />

x=50°<br />

16. 3<br />

4<br />

or 1.33<br />

Difficulty: Medium<br />

Strategic Advice: Eva l uate eac h side of t h e equation b y<br />

p l ugging into t h e definitions, t h en so l ve <strong>for</strong> a.<br />

Getting to <strong>the</strong> Answer:<br />

::::} (3a) 2(4) 3(3a) 8 + 9a<br />

4 ¢= (3a) = 3( 4) + 2(3a) = 12 + 6a<br />

Since t h ese are equa l , 8 + 9a = 12 + 6a<br />

9a=4 + 6a<br />

1<br />

17. 2<br />

or .5<br />

3a=4 4 a=-3<br />

Difficulty: Hig h<br />

Strategic Advice: Find t h e possi b l e va l ues of s an d d , t h en<br />

determine w h ic h wi ll give you t h e l argest s l ope t h roug<br />

t h e two points. Notice t h atx and y are not in t h eir usua h<br />

positions in t h e equation.<br />

l<br />

Getting to <strong>the</strong> Answer:<br />

First, p l ug (5, s) into t h e equation of t h e function:<br />

5=2s + 3<br />

2=2s 2<br />

1 =5 2<br />

s= 1,- 1<br />

Now do t h e same wit h ( 11, d) :<br />

11=2 d2 +3<br />

8=2 d2<br />

4= d2 d =2,-2 d -s d -s<br />

T h e s l ope t h roug h (5,s) and (11, d) is TT-=s =-6-. To<br />

make this as large as possible, choose d = 2, s = -1 so that<br />

t h e s l ope dis t h is: -s 2- (-1)<br />

6 6 = _3_<br />

6 =2 1<br />

18. 30<br />

Difficulty: Hig h<br />

Strategic Advice: Write out a c h art wit h rate, time, and<br />

distance and fi ll in w h at you know. T en try to use t h at to<br />

so l ve <strong>for</strong> t h e distance. If it took h er t h ours to get to t h e<br />

circus, and t h e tota l trip was 2.2 h ours, h ow l ong (in terms<br />

oft) did s h e spend returning?<br />

Getting to <strong>the</strong> Answer:<br />

2 h ours and 12 min= 2 + = 2.2 h ours<br />

rate time distance<br />

To circus 30 mp<br />

From circus 25 mp h t<br />

2.2-t d<br />

Now use t h e rate <strong>for</strong>mu l a r x t = d <strong>for</strong> b ot h parts of t h e trip:<br />

30 Xt= d<br />

25 x (2.2-t) = d

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