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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Eight Answers and Explanations I<br />

747<br />

3. E<br />

Difficulty: Medium<br />

Strategic Advice: Here you're working with a system of<br />

equations, one of which has two variables and one that has<br />

one variable. A good way to solve this is substitution.<br />

Getting to <strong>the</strong> Answer:<br />

If 2a = 1 0, <strong>the</strong>n dividing both sides by 2 gives you a= 5.<br />

If a = 5, <strong>the</strong>n a2 - 16 = b2 can be written 52 - 16 = b2, or<br />

25 - 16 =b2, or 9 =b2. If b2 is 9, <strong>the</strong>n b must be 3 or -3,<br />

and (E), 3, could be a value <strong>for</strong> b.<br />

4. A<br />

Difficulty: Medium<br />

Strategic Advice: The sequence that you're given has 8<br />

numbers, 4 of which are odd and 4 of which are even. You<br />

want to know how <strong>the</strong> sum of those numbers would change<br />

if <strong>the</strong> individual numbers changed by various amounts.<br />

You don't need to start adding up <strong>the</strong> numbers in <strong>the</strong><br />

sequence-you're only concerned with how <strong>the</strong> sum would<br />

change, not what its value is.<br />

Getting to <strong>the</strong> Answer:<br />

There are 4 odd numbers in <strong>the</strong> sequence. The question<br />

tells you that each odd-valued term will be increased by<br />

3. Then <strong>the</strong> sum will increase by 4 x 3, or 12. If each<br />

even-valued term is decreased by 2, that's <strong>the</strong> same as<br />

decreasing 4 of <strong>the</strong> terms by 2 each, or <strong>the</strong> entire sequence<br />

by 4 x 2, or 8. So <strong>the</strong> sum of <strong>the</strong> sequence will increase<br />

by 12 and decrease by 8. That's like adding 12 and <strong>the</strong>n<br />

subtracting 8, which is <strong>the</strong> same as adding 4, (A).<br />

5. E<br />

Difficulty: Medium<br />

Strategic Advice: If you're not sure what <strong>the</strong> various<br />

trans<strong>for</strong>mations of y = x2 presented in <strong>the</strong> answer choices<br />

look like, you can try plugging in a few points from <strong>the</strong> graph<br />

to see which equation works. ( 1, 1) is a good point to test.<br />

Getting to <strong>the</strong> Answer:<br />

y= 1,x= 1<br />

1 = 2 - (12)<br />

1=2-1<br />

1 = 1<br />

Only (E) passes through this point.<br />

6. E<br />

Difficulty: Medium<br />

Strategic Advice: You've got a bunch of lines and angles<br />

here, with a triangle in <strong>the</strong> middle. One of <strong>the</strong> interior<br />

angles of <strong>the</strong> triangle is 60°. The o<strong>the</strong>r two interior angles of<br />

<strong>the</strong> triangle are unknown, but <strong>the</strong> one on <strong>the</strong> right and <strong>the</strong><br />

angle marked 11 5° make up a straight line, or 180°.<br />

That means <strong>the</strong> interior angle on <strong>the</strong> right measures<br />

1 80° - 115°, or 65°. The three interior angles of a triangle<br />

add up to 1 80°, so <strong>the</strong> third interior angle of <strong>the</strong> triangle,<br />

<strong>the</strong> one on <strong>the</strong> left, must measure 180 - 60 - 65, or 55°.<br />

Getting to <strong>the</strong> Answer:<br />

That 55° interior angle of <strong>the</strong> triangle is on <strong>the</strong> same side<br />

of <strong>the</strong> straight line as <strong>the</strong> angle labeled r 0 , so r must be<br />

180 - 55, or 1 25°. The 55° angle and <strong>the</strong> angle labeled 5°<br />

are vertical angles, so <strong>the</strong>y are equal and 5 = 55. There<strong>for</strong>e,<br />

r - 5 = 125 - 55, or 70, (E).<br />

7. A<br />

Difficulty: Medium<br />

Strategic Advice: The date of <strong>the</strong> second Friday in<br />

December depends on what day <strong>the</strong> first of <strong>the</strong> month falls<br />

on. If <strong>the</strong> first of <strong>the</strong> month is a Friday, <strong>the</strong>n <strong>the</strong> 8th of <strong>the</strong><br />

month is also a Friday, since 1 + 7 is 8. If <strong>the</strong> first of <strong>the</strong><br />

month is a Tuesday, <strong>the</strong>n <strong>the</strong> first Friday is <strong>the</strong> 4th, and <strong>the</strong><br />

second Friday is <strong>the</strong> 1 1th.<br />

Getting to <strong>the</strong> Answer:<br />

If you try putting <strong>the</strong> first of <strong>the</strong> month on each of <strong>the</strong> days<br />

of <strong>the</strong> week, you'll find that <strong>the</strong> latest possible date <strong>for</strong> <strong>the</strong><br />

first Friday occurs when <strong>the</strong> first of <strong>the</strong> month falls on a<br />

Saturday. In that case, <strong>the</strong> first Friday falls on <strong>the</strong> 7th, and<br />

<strong>the</strong> second Friday falls on <strong>the</strong> 1 4th, (A).<br />

8. c<br />

Difficulty: High<br />

Strategic Advice: You want to find <strong>the</strong> ratio of <strong>the</strong> length of<br />

a side of <strong>the</strong> square to <strong>the</strong> length of a side of <strong>the</strong> triangle.<br />

You're told that <strong>the</strong> square and <strong>the</strong> triangle have equal<br />

perimeters. The perimeter of any polygon is <strong>the</strong> sum of<br />

<strong>the</strong> lengths of its sides. In an equilateral triangle, all three<br />

sides have <strong>the</strong> same length. Call <strong>the</strong> length of each side of<br />

<strong>the</strong> equilateral triangle t. Then <strong>the</strong> perimeter of equilateral<br />

triangle Eis 3t. In a square, all four sides have <strong>the</strong> same<br />

length. Call <strong>the</strong> length of each side of <strong>the</strong> square 5. Then <strong>the</strong><br />

perimeter of square S is 45.

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