12.Practice.Tests.for.the.SAT_2015-2016_1128p

12 Practice Tests for the SAT
654 Practice Test Seven Answers and Explanations
Getting to the Answer:
The box has dimensions 10 inches by 1 0 inches by 1 0
inches. Since each CD is 5 inches in length, she can fit 1 i,
or 2, rows of CDs along the length of the box. Each CD is 5
inches in width, so she can fit 1 i, or 2, rows of CDs along
the width of the box. Finally, each CD is -t inch deep, so she
can fit 1 0 + i· or 20, rows of CDs along the depth of the
box. Finally, 2 times 2 times 20 equals 80.
15. 7.5
Difficulty: Medium
Strategic Advice: Look for similar angles to help you
determine values.
Getting to the Answer:
Since EF is parallel to CH, angle DEF = angle C and angle
OFE = angle H. Since angles DEF and OFE of WEF are
equal to angles C and H, respectively, of WCH, the
triangles are similar. This tells you that corresponding sides
of the two triangles are in proportion to one another. Since
DE = EC, DE, a side of WEF, is half the length of DC, a
corresponding side of WCH. So all the sides of WGH are
twice as long as the corresponding sides of WEF. Also, the
height of OCH must be twice the corresponding height of
DEF. Since the area of a triangle is -tbh, the area of WCH
is four times the area of WEF. Since the area of WCH is
30, the area of WEF is 7.5.
16. 306, 324, 342, 360, 378, or 396
Difficulty: Medium
Strategic Advice: You only need to find one number that
fits the description and grid that in. Use the divisibility rules
to help you find a correct answer.
Getting to the Answer:
A number is divisible by 9 if the sum of its digits is divisible
by 9. You don't need to check divisibility by 3, since a
number that is divisible by 9 must be divisible by 3. A
number is divisible by 6 if it's an even number divisible
by 3. So you're looking for an even number between 300
and 400 that has digits that sum to a multiple of 9. With a
little trial and error, you can find a number that works. For
example, 306 works because it's an even number whose
digits add up to 9.
Another approach is to multiply 3, 6, and 9. The result is 1 62,
which is not between 300 and 400. However, if you multiply
162 by 2, you get 324, which is an acceptable answer.
7
11. TS
Difficulty: Medium
Strategic Advice: Probability is
number of desired outcomes
total number of possible outcomes
·
Getting to the Answer:
The coins worth more than 5 cents are the quarters and
dimes, so the number of desired outcomes is 3 + 4, or 7.
The total number of possible outcomes is the same as the
total number of coins, which is 3 + 4 + 2 + 6, or 15.
So the probability is 1
7
5
.
18. O < x< 6
Difficulty: High
Strategic Advice: First determine the diameters of the two
circles and then think about how they could intersect.
Getting to the Answer:
Circle A has an area of 91t. This means the radius must be
3(321t = 91t), so circle A has a diameter of 6. Circle B has a
circumference of 61t, so it has a diameter of 6. These two
circles are the same! If the circles were tangent, there would
be no length between the two points of intersection (since
there would only be one point of intersection). However, if
you moved them a little closer together, the one point would
become two, so the distance could be anything greater than
0. If the circles were concentric, they would intersect at an
infinite number of points. However, if you moved them a little
apart, they would intersect at just two points that are almost
the diameter, so the maximum value is 6.
SECTION 6
1. B
Difficulty: Low
In this sentence, subjects is a noun, so it needs to be
modified by the adjective general, not the adverb generally.
Choices (C) and (E) correct the modifier, but they introduce
new errors.