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12.Practice.Tests.for.the.SAT_2015-2016_1128p

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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Nine Answers and Explanations 81 3<br />

I<br />

Getting to <strong>the</strong> Answer:<br />

Since -€ 4 is perpendicular to -€ 2<br />

, all <strong>the</strong> angles that are<br />

<strong>for</strong>med where those two lines cross are right angles.<br />

And, since .e 1 is parallel to -€ 2<br />

, <strong>the</strong> angles that are <strong>for</strong>med<br />

where -€ 4 and .e 1 meet are also right angles. That means<br />

that .e 1 and .e 4 must also be perpendicular to each o<strong>the</strong>r,<br />

which means that statement I is true. That means you can<br />

eliminate (B) and (E).<br />

-€ 3 also crosses <strong>the</strong> two parallel lines and toge<strong>the</strong>r with<br />

-€ 4 creates a triangle between <strong>the</strong>m. Since all <strong>the</strong> angles<br />

<strong>for</strong>med where -€ 2<br />

and -€ 4 meet are right angles, <strong>the</strong> triangle<br />

is a right triangle. One of <strong>the</strong> o<strong>the</strong>r angles of <strong>the</strong> triangle<br />

measures G0, but what about <strong>the</strong> third angle of <strong>the</strong> triangle?<br />

Well, that angle is <strong>for</strong>med by <strong>the</strong> same lines that <strong>for</strong>m <strong>the</strong><br />

angle labeled b0, so that angle inside <strong>the</strong> triangle must<br />

also measure b0• Since <strong>the</strong> three angles inside <strong>the</strong> triangle<br />

measure G0 , b0, and go0, and <strong>the</strong> sum of <strong>the</strong> angles in a<br />

triangle is always 1 80°, G + b + go = 1 80, which means<br />

that G + b = go, statement Ill is true. Now you can eliminate<br />

(A) and (C), and since (D) is <strong>the</strong> only one left, it must be<br />

correct.<br />

Notice that you didn't even have to deal with statement II once<br />

you figured out that statements I and Ill were true. This often<br />

happens in Roman numeral questions. Just <strong>for</strong> <strong>the</strong> record,<br />

though, statement II is not necessarily true. You know that<br />

G + b = go, so if G = b, <strong>the</strong>n G and b are each 45. However,<br />

although that's how G and b look in <strong>the</strong> figure, <strong>the</strong>re's no<br />

in<strong>for</strong>mation <strong>the</strong>re that would indicate that b could just as easily<br />

be a 46°, a 43°, or a 50° angle, so statement II is false.<br />

10. B<br />

Difficulty: Medium<br />

Strategic Advice: Take this question one step at a time.<br />

Getting to <strong>the</strong> Answer:<br />

A bicyclist riding at 12 miles an hour <strong>for</strong> 2 hours travels<br />

twice as far as a hiker. How far does <strong>the</strong> bicyclist travel?<br />

That's easy, 12 miles an hour <strong>for</strong> 2 hours is just 12 x 2 or<br />

24 miles. If <strong>the</strong> bicyclist travels twice as far as <strong>the</strong> hiker, and<br />

<strong>the</strong> bicyclist travels 24 miles, <strong>the</strong> hiker must travel 12 miles,<br />

since 24 is twice 12. The hiker walks at 4 miles an hour <strong>for</strong><br />

a total of 12 miles. Since 4 x 3 = 12, <strong>the</strong> hiker must walk<br />

<strong>for</strong> 3 hours at 4 miles an hour to go a total of 12 miles, so<br />

<strong>the</strong> correct answer choice is (B).<br />

11. D<br />

Difficulty: Medium<br />

Strategic Advice: Remember, solving inequalities is <strong>the</strong> same<br />

as solving equations with one exception-if you multiply or<br />

divide by a negative number, you have to change <strong>the</strong> direction<br />

of <strong>the</strong> inequality sign. You can solve this one pretty easily.<br />

Getting to <strong>the</strong> Answer:<br />

Start by adding 2b to each side, and <strong>the</strong>n divide by 2:<br />

2G -2b

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