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12 Practice <strong>Tests</strong> <strong>for</strong> <strong>the</strong> <strong>SAT</strong><br />

Practice Test Ten Answers and Explanations<br />

1<br />

12. S<br />

or .2<br />

Difficulty: Medium<br />

Strategic Advice: Don't let <strong>the</strong> decimals throw you.<br />

Proportions always work <strong>the</strong> same way, without respect to<br />

<strong>the</strong> kinds of numbers <strong>the</strong>y relate.<br />

Getting to <strong>the</strong> Answer:<br />

_l?_ = <br />

18 2.4<br />

18x = (1.5)(2.4)<br />

x=0.2<br />

1<br />

13. 3 or .333<br />

Difficulty: Medium<br />

Strategic Advice: Fractional exponents are subject to <strong>the</strong><br />

same rules as any o<strong>the</strong>r kind of exponent, so if you know<br />

those rules, you'll slice through questions like this one<br />

quickly and efficiently. When we have <strong>the</strong> same base on<br />

each side, we can set <strong>the</strong> exponents equal and solve <strong>for</strong> b.<br />

Getting to <strong>the</strong> Answer:<br />

aba3 = ab +3<br />

b+3=J_Q<br />

3<br />

b=J_Q-3=_1_<br />

3 3<br />

14. 8<br />

Difficulty: Medium<br />

Strategic Advice: On Test Day, look <strong>for</strong> clues that tell you<br />

how to solve <strong>the</strong> problem. The words greater than in this<br />

question suggest that you are solving an inequality.<br />

Getting to <strong>the</strong> Answer:<br />

0.40x> 2.8<br />

x> 2.8<br />

0.40<br />

x>7<br />

15. 0<br />

Difficulty: High<br />

Strategic Advice: Look <strong>for</strong> a pattern.<br />

Getting to <strong>the</strong> Answer:<br />

The terms repeat in groups of 8, and <strong>the</strong> sum of every<br />

such group is zero. The 88th term will be <strong>the</strong> last of 1 1<br />

repetitions of this cycle.<br />

16. 9<br />

Difficulty: High<br />

Strategic Advice: Questions with square roots can be<br />

intimidating. However, <strong>the</strong>y are solved like any o<strong>the</strong>r type of<br />

algebra question. Treat <strong>the</strong> square root as a single quantity<br />

until you isolate it on one side of <strong>the</strong> equation. Then square<br />

both sides to get rid of <strong>the</strong> square root.<br />

Getting to <strong>the</strong> Answer:<br />

14<br />

=7<br />

vX=5<br />

l± = vX=S 7 22=( v'X=5)2<br />

17. 26<br />

4 =x- 5<br />

9=x<br />

Difficulty: High<br />

Strategic Advice: This question challenges you to rearrange<br />

in clever and creative ways <strong>the</strong> in<strong>for</strong>mation you are given in<br />

<strong>the</strong> question stem. Notice we can slide a to <strong>the</strong> right and b up<br />

to make our shape a rectangle - much easier to work with!<br />

Getting to <strong>the</strong> Answer:<br />

P=2r+2s<br />

=2(r +s)<br />

=2(13)=26<br />

5<br />

18. G<br />

or .833<br />

Difficulty: High<br />

Strategic Advice: One way to make a question very<br />

daunting to most test takers is to present data in relatively<br />

complex <strong>for</strong>m. Use algebra to manipulate <strong>the</strong> situation by<br />

rendering complicated-looking relationships into simple<br />

terms.<br />

Getting to <strong>the</strong> Answer:<br />

x3 = -1x2<br />

2<br />

Divide both sides by x2 since x "* 0.<br />

x =<br />

1<br />

-<br />

2<br />

y3 = -1y2<br />

3

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