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Handbook of the History of Logic: - Fordham University Faculty

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Pro<strong>of</strong>.<br />

Treatments <strong>of</strong> <strong>the</strong> Paradoxes <strong>of</strong> Self-reference 593<br />

(1)* ‘a’ signifies only that ‘a’ is not true and that B is C Assumed<br />

(2)* ‘a’ is not true Assumed<br />

(3)* It is not wholly as ‘a’ signifies (2)*, (Def. <strong>of</strong> truth)<br />

(4)* It is not <strong>the</strong> case that ‘a’ is not true and B is C<br />

(1)*, (3)*, (T1.1)<br />

(5)* ‘a’ istrueorB is not C (4)*<br />

(6)* ‘a’ signifies that ‘a’ istrueorB is not C (1)*, (2)*–(5)*, (P2)<br />

(7)* ‘a’ signifies that B is C (1)*, (P2)<br />

(8)* ‘a’ istrueorB is not C, andBis C, <strong>the</strong>refore ‘a’ istrue<br />

(9)* ‘a’ signifies that ‘a’ is true. (P2)<br />

This reasoning is a bit more confusing, and not only because Bradwardine jumps<br />

between first order claims ((4)*, (5)* and (8)*) and claims about <strong>the</strong> examined<br />

paradoxical sentence and its signification ((1)*, (2)*, (3)*, (6)*, (7)* and (9)*)<br />

more than in <strong>the</strong> previous pro<strong>of</strong>. It is, however, possible to see what really happens.<br />

After laying <strong>the</strong> ground with <strong>the</strong> two assumptions (1)* and (2)*, Bradwardine<br />

construes <strong>the</strong> disjunctive signification (6)* through <strong>the</strong> conditional pro<strong>of</strong> (2)*–<br />

(5)*. The he excludes <strong>the</strong> latter disjunct at (7)*, and proceeds with <strong>the</strong> support<br />

<strong>of</strong> <strong>the</strong> inference (8)* to <strong>the</strong> main goal (9)*.<br />

At (7)* Bradwardine makes a choice. He could at that step exclude <strong>the</strong> former<br />

disjunct by taking <strong>the</strong> corresponding proposition “a’ signifies that ‘a’ isnot<br />

true’ and using it in a similar way, to achieve instead <strong>of</strong> step (9)* <strong>the</strong> claim<br />

“a’ signifies that B is not C.’ That is, he could reason as follows. Assume<br />

‘a’ :(¬T ‘a’&p). Thus ¬T ‘a’ →¬(¬T ‘a’&p) → (T ‘a’ ∨¬p) →¬p. By (P2)*,<br />

it follows that ‘a’ :(¬T ‘a’&p&¬p), and since any sentence follows from <strong>the</strong> contradiction<br />

(¬T ‘a’&p&¬p), ‘a’ signifies everything, including its own truth.<br />

For quite obvious reasons, this is not <strong>the</strong> way Bradwardine goes. He wants to<br />

prove <strong>the</strong> <strong>the</strong>sis (T2) in a sensible way, and for this he needs “a’ signifies that ‘a’<br />

is true’ but not much more. Thus, he reasons as follows. Assume ‘a’ :(¬T ‘a’&p).<br />

Thus ¬T ‘a’ → ¬(¬T ‘a’&p) → (T ‘a’ ∨¬p) → T ‘a’. By (P2)*, it follows now<br />

that ‘a’ :(¬T ‘a’&p&T ‘a’), which is a much more sensible kind <strong>of</strong> inconsistence.<br />

However, this way <strong>of</strong> looking at <strong>the</strong> pro<strong>of</strong> makes it apparent that Bradwardine is in<br />

itself is not true, for example, that B is C, <strong>the</strong>n supposing that A is not true, it follows that it<br />

is not wholly as A signifies, that is, that A is not true and B is C, whence it is not <strong>the</strong> case that<br />

A is not true and that B is C, and so, by postulate (P4), A is true or B is not C, andso,by<br />

postulate (P2), A signifies that A is true or B is not C, and since it signifies <strong>the</strong> opposite <strong>of</strong> <strong>the</strong><br />

second part <strong>of</strong> this disjunction (we supposed), namely, that B is C, we have by postulate (P5),<br />

from this disjunction with <strong>the</strong> opposite <strong>of</strong> its second part that <strong>the</strong> first part follows, namely, that<br />

A is true. Hence by postulate (P2), A signifies A to be true.” [Bradwardine, internet, 45]. (P4)<br />

and (P5) are ordinary principles <strong>of</strong> propositional logic; see [Bradwardine, internet, 39].

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