المعلم رياضيات الصف 12
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_<br />
sec A sec B<br />
sec (A - B) ≟ <br />
1 + tan A tan B )27<br />
1_<br />
cos A ⋅ 1_<br />
<br />
sec (A - B) ≟<br />
__ cos B<br />
<br />
<br />
1 + _ sin A<br />
cos A ⋅ _ sin B <br />
cos B <br />
1_<br />
cos A ⋅ 1_<br />
<br />
cos B<br />
sec (A - B) ≟ __<br />
<br />
1 + _ sin A<br />
cos A ⋅ _ sin B ⋅ _ cos A cos B<br />
cos B cos A cos B <br />
__<br />
1<br />
sec (A - B) ≟ <br />
cos A cos B + sin A sin B <br />
sec (A - B) ≟ <br />
cos (A - B) <br />
الوحدة 1 ملحق الإجابات<br />
الوحدة 1 المتطابقات والمعادالت المثلثية<br />
اختبار منتصف الوحدة، ص (24)<br />
<br />
_ sin2 θ<br />
_<br />
cot 2 cot θ<br />
θ + 1 ≟ <br />
cos θ ∙ sin θ )10<br />
__<br />
csc 2 cos θ<br />
θ ≟ <br />
cos θ ∙ sin θ ∙ sin θ <br />
csc 2 θ ≟ <br />
1_<br />
sin 2 θ <br />
csc 2 θ = csc 2 θ ✓<br />
_<br />
cos θ csc θ<br />
≟ 1 )11<br />
cot θ<br />
cos θ <br />
1_<br />
__ sin θ <br />
≟ 1<br />
cot θ<br />
_ cos θ<br />
sin θ <br />
_<br />
cot θ ≟ 1<br />
_<br />
_ cot θ<br />
cos θ ≟ 1<br />
1 = 1 ✓<br />
sin θ tan θ<br />
≟ (1 + cos θ) sec θ )<strong>12</strong><br />
1 - cos θ<br />
_<br />
sin θ ( sin θ<br />
cos θ )<br />
_<br />
1 - cos θ ≟ (1 + cos θ) 1_<br />
cos θ <br />
sin2 θ<br />
_ cos θ<br />
<br />
<br />
1 - cos θ ≟ 1_<br />
cos θ + 1<br />
cos θ ∙ 1_<br />
1 - cos θ ≟ 1_<br />
sin<br />
__<br />
2 θ<br />
cos θ (1 - cos θ) ≟ 1_<br />
cos θ + 1<br />
cos θ + 1<br />
1 - cos<br />
__<br />
2 θ<br />
cos θ (1 - cos θ) ≟ 1_<br />
__<br />
(1 - cos θ)(1 + cos θ) 1_<br />
<br />
cos θ + 1<br />
≟ <br />
cos θ(1 - cos θ) cos θ + 1<br />
_ 1 + cos θ<br />
cos θ ≟ 1_<br />
cos θ + 1<br />
1_<br />
cos θ + 1 = 1_<br />
_ cos θ sin θ<br />
cos θ + 1 ✓<br />
tan θ (1 - sin θ) ≟ <br />
1 + sin θ )13<br />
_<br />
_<br />
cos θ sin θ<br />
tan θ (1 - sin θ) ≟ <br />
1 + sin θ ∙ 1 - sin θ<br />
1 - sin θ <br />
__<br />
cos θ sin θ(1 - sin θ)<br />
tan θ (1 - sin θ) ≟ <br />
1 - sin 2 θ<br />
__<br />
cos θ sin θ(1 - sin θ)<br />
tan θ (1 - sin θ) ≟ <br />
cos 2 θ<br />
__<br />
sin θ(1 - sin θ)<br />
tan θ (1 - sin θ) ≟ <br />
cos θ<br />
_<br />
tan θ (1 - sin θ) ≟ sin θ ∙ (1 - sin θ)<br />
cos θ<br />
tan θ (1 - sin θ) = tan θ (1 - sin θ) ✓<br />
cot θ = _ <strong>12</strong><br />
9 )14b<br />
_ cos θ<br />
sin θ = _ <strong>12</strong>_<br />
15 <br />
9_ = <strong>12</strong>_<br />
15 9 <br />
<strong>12</strong>_<br />
9 = _ <strong>12</strong><br />
9<br />
بما أن <br />
cot θ = cos θ _<br />
إذن θ sin<br />
<br />
<br />
1_<br />
sec (A - B) = sec (A - B) ✓<br />
sin (A + B) sin (A - B) ≟ sin 2 A - sin 2 B )28<br />
(sin A cos B + cos A sin B) (sin A cos B - cos A sin B)<br />
≟ sin 2 A – sin 2 B<br />
(sin A cos B) 2 - (cos A sin B) 2 ≟ sin 2 A - sin 2 B<br />
sin 2 A cos 2 B - cos 2 A sin 2 B ≟ sin 2 A - sin 2 B<br />
sin 2 A cos 2 B + sin 2 A sin 2 B -<br />
sin 2 A sin 2 B - cos 2 A sin 2 B ≟ sin 2 A - sin 2 B<br />
sin 2 A (cos 2 B + sin 2 B) - sin 2 B (sin 2 A + cos 2 A) ≟<br />
sin 2 A - sin 2 B<br />
(sin 2 A)(1) - (sin 2 B)(1) ≟ sin 2 A - sin 2 B<br />
sin 2 A - sin 2 B = sin 2 A - sin 2 B ✓<br />
1_<br />
cot (A + B) = <br />
tan (A + B) )30<br />
1_<br />
= <br />
<br />
tan A + tan B<br />
_<br />
1 - tan A tan B <br />
_<br />
1 - tan A tan B<br />
= <br />
tan A + tan B <br />
= 1 - 1_<br />
__<br />
cot A ⋅ 1_<br />
cot B <br />
1_<br />
cot A + 1_<br />
_<br />
cot B <br />
_<br />
cot A cot B - 1<br />
cot A cot B<br />
⋅ <br />
cot A cot B <br />
= <br />
cot A + cot B <br />
d = √ ÇÇÇÇÇÇÇÇÇÇÇÇÇ<br />
(cos A - cos B) 2 + (sin A - sin B) 2 )31<br />
d 2 = (cos A - cos B) 2 + (sin A - sin B) 2<br />
d 2 = (cos 2 A - 2 cos A cos B + cos 2 B) + (sin 2 A - 2 sin A<br />
sin B + sin 2 B)<br />
d 2 = cos 2 A + sin 2 A + cos 2 B + sin 2 B - 2 cos A cos B -d<br />
d 2 = 1 + 1 - 2 cos A cos B - 2 sin A sin B<br />
2 sin A sin B<br />
d 2 = 2 - 2 cos A cos B - 2 sin A sin B = 2 - 2 cos (A-B)<br />
43E