المعلم رياضيات الصف 12
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الوحدة 1 ملحق الإجابات<br />
الدرس 1-4 , ص ,30) (29<br />
tan 2θ ≟ __ 2<br />
<br />
cot θ - tan θ )16<br />
2<br />
tan 2θ ≟ __<br />
cot θ - tan θ ⋅ _ tan θ<br />
tan θ <br />
2 tan θ<br />
tan 2θ ≟ __<br />
cot θ tan θ - tan 2 θ <br />
tan 2θ ≟ _ 2 tan θ<br />
1 - tan 2 θ <br />
tan 2θ = tan 2θ ✓<br />
__<br />
d = v 2 sin 2 (45° + A)<br />
g <br />
=<br />
__<br />
v 2 sin (90° + 2A)<br />
g <br />
sin θ_ cos θ_<br />
2<br />
2 sin θ_<br />
cos<br />
_<br />
θ_<br />
2 2 <br />
<br />
2<br />
sin 2 ( θ_<br />
2 )<br />
_<br />
_<br />
2 ≟ sin θ<br />
2 )17<br />
_<br />
≟ sin θ<br />
2 <br />
_<br />
≟ sin θ<br />
2 2 <br />
_ sin θ<br />
2 = sin _ θ<br />
2 ✓<br />
)20 إذا كانت θ = 45° + A<br />
___<br />
= v 2 (sin 90° cos 2A + cos 90° sin 2A)<br />
g<br />
<br />
=<br />
__<br />
v 2 (1 ⋅ cos 2A + 0 ⋅ sin 2A)<br />
g <br />
_<br />
= v 2 cos 2A<br />
g <br />
__<br />
d = v 2 sin 2 (45° - A)<br />
g <br />
=<br />
__<br />
v 2 sin (90° - 2A)<br />
g <br />
إذا كانت θ = 45° - A<br />
___<br />
= v 2 (sin 90° cos 2A - cos 90° sin 2A)<br />
g<br />
<br />
=<br />
__<br />
v 2 (1 ⋅ cos 2A - 0 ⋅ sin 2A)<br />
g <br />
_<br />
= v 2 cos 2A<br />
g <br />
f (θ) = 4( sin θ cos π_ 4<br />
4<br />
2<br />
y<br />
cos θ sin π_ 4 )<br />
π<br />
θ<br />
)26a<br />
_<br />
_<br />
sin θ ∙ sec θ<br />
≟ (sec θ + 1) cot θ )15<br />
sec θ - 1<br />
_<br />
sec θ + 1<br />
sec θ + 1 ∙ sin θ ∙ sec θ ≟ (sec θ + 1) cot θ<br />
sec θ - 1<br />
__<br />
sin θ ∙ sec θ (sec θ + 1)<br />
≟ (sec θ + 1) cot θ<br />
sec 2 θ - 1<br />
sin θ ∙ 1_<br />
(sec θ + 1)<br />
__<br />
cos θ<br />
≟ (sec θ + 1) cot θ<br />
tan 2<br />
_<br />
θ<br />
sin θ (sec θ + 1)<br />
__<br />
cos θ<br />
≟ (sec θ + 1) cot θ<br />
tan 2 θ<br />
__<br />
tan θ (sec θ + 1)<br />
≟ (sec θ + 1) cot θ<br />
tan 2 θ<br />
_<br />
sec θ + 1<br />
1<br />
_<br />
sec θ + 1 ≟ (sec θ + 1) cot θ<br />
tan θ<br />
∙ <br />
1_<br />
≟ (sec θ + 1) cot θ<br />
tan θ<br />
(sec θ + 1) cot θ = (sec θ + 1) cot θ ✓<br />
sin 2 θ ∙ tan 2 θ ≟ tan 2 θ - sin 2 θ )16<br />
sin 2 θ ∙ tan 2 θ ≟ _<br />
sin2 θ<br />
cos 2 θ - sin2 θ<br />
__<br />
sin 2 θ ∙ tan 2 θ ≟ sin2 θ - sin 2 θ cos 2 θ<br />
<br />
cos 2 θ<br />
__<br />
sin 2 θ ∙ tan 2 θ ≟ sin2 θ (1 - cos 2 θ)<br />
<br />
cos 2 θ<br />
_<br />
sin 2 θ ∙ tan 2 θ ≟ sin2 θ (sin 2 θ)<br />
<br />
cos 2 θ<br />
_<br />
sin 2 θ ∙ tan 2 θ ≟ sin 2 θ ∙ sin2 θ<br />
cos 2 θ <br />
sin 2 θ ∙ tan 2 θ = sin 2 θ ∙ tan 2 θ ✓<br />
_<br />
cos θ ∙ sin θ<br />
cot θ (1 - cos θ) ≟ <br />
1 + cos θ )17<br />
_<br />
_<br />
cos θ ∙ sin θ<br />
cot θ (1 - cos θ) ≟ <br />
1 + cos θ ∙ 1 - cos θ<br />
1 - cos θ <br />
__<br />
cos θ ∙ sin θ (1 - cos θ)<br />
cot θ (1 - cos θ) ≟ <br />
1 - cos 2 θ<br />
__<br />
cos θ ∙ sin θ (1 - cos θ)<br />
cot θ (1 - cos θ) ≟ <br />
sin 2 θ<br />
__<br />
cos θ (1 - cos θ)<br />
cot θ (1 - cos θ) ≟ <br />
sin θ<br />
cot θ (1 - cos θ) ≟ _ cos θ (1 - cos θ)<br />
sin θ<br />
cot θ (1 - cos θ) = cot θ (1 - cos θ) ✓<br />
cos 30˚ cos θ + sin 30˚ sin θ ≟ sin 60˚ cos θ + cos 60˚ sin θ )23<br />
_<br />
_<br />
√ Ç 3 Ç<br />
cos θ + 1_ sin θ = √ 3 cos θ + 1_<br />
2 2 2 2 sin θ ✓<br />
4 sin ( θ - π _<br />
4 ); )26b<br />
4 sin ( θ - π _<br />
4 ) = 4 ( sin θ cos π _<br />
4 - cos θ sin π _<br />
4 ) ,<br />
الوحدة 1 ملحق االإجابات 43F